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2 years ago

DONT FORGET TO GRAPH IT!! ALL QUESTIONS THAT DONT ANSWER MY QUESTION, WILL BE REPORTED!

Mathematics

1 answer:

sdas [7]2 years ago

5 0

Answer:

look on bottom

Step-by-step explanation:

heres how to do it:

select the last arrow, the one that is not dark and is pointing right

drop it on the number 3

done

hope this helps!

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If bill has 300 dresses with a weight of 30 pounds each. How do you find the average weight of all of the dresses with the volum

maria [59]

The answer is 9000 hope this helps

3 0

3 years ago

An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand

Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

b) We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

Part b

We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

4 0

3 years ago

At an animal shelter there are 15dogs, 12 cats, 3 snakes and 5 parakeets . What percent of the number of cats is the number of d

madreJ [45]

Total number of animals at the shelter = 15 + 12 +3 + 5 = 35 animals.
Let the total number of animals be represented by 100%
There are 15 dogs and 12 cats so:
% Number of dogs = 15/35 x 100% = 42.86%
% Number of cats = 12/35 x 100% = 34.28%

6 0

3 years ago

HELP PLEASE <br><br><br> Simplify.

maksim [4K]

Simplifying
2x + -3(3 * 0.6x + 2.7)

Multiply 3 * 0.6
2x + -3(1.8x + 2.7)

Reorder the terms:
2x + -3(2.7 + 1.8x)
2x + (2.7 * -3 + 1.8x * -3)
2x + (-8.1 + -5.4x)

Reorder the terms:
-8.1 + 2x + -5.4x

Combine like terms: 2x + -5.4x = -3.4x
-8.1 + -3.4x

7 0

3 years ago

Determine the domain and range of the following

Tasya [4]

Answer:

Domain: (-3,-2,0,1,2,3)

Range: (9,4,1,0,1,4,9)

Step-by-step explanation:

5 0

3 years ago