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2 years ago

15 cm 4 cm cm V=____cm3

Mathematics

1 answer:

bonufazy [111]2 years ago

8 0

Answer:

V=(πr^2 x h)/3

lets use π as 3.14 cause I dont know what pi u using

3.14 x 4^2 x 15 = 753.6/3 = 251.2

If you're using π as your pi, than just replace 3.14 by π on calculator

Hope that answers your question

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A building 220 feet casts a 100 foot long shadow. If a person stands at the end of the shadow and looks up to the top of the bui

kaheart [24]

Answer:

65.56°

Step-by-step explanation:

= We solve the above question using the Trigonometric function of Tangent

tan θ = Opposite/Adjacent

Opposite = 220 feet = Height of the building

Adjacent = 100 feet = Length of the shadow

Hence,

tan θ = 220/100

tan θ = 2.2

= arctan(2.2)

= 65.55604522°

Approximately = 65.56°

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2 years ago

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ohaa [14]

Answer:

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Step-by-step explanation:

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2 years ago

Need help with Calculus 1 inverse trig functions

lidiya [134]

Answer:

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}$

Step-by-step explanation:

<u>The Derivative of a Function</u>

The derivative of f, also known as the instantaneous rate of change, or the slope of the tangent line to the graph of f, can be computed by the definition formula

$\displaystyle f'(x)=\lim\limits_{\Delta x \rightarrow 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}$

There are tables where the derivative of all known functions are provided for an easy calculation of specific functions.

The derivative of the inverse tangent is given as

$\displaystyle (tan^{-1}u)'=\frac{u'}{1+u^2}$

Where u is a function of x as provided:

$y=3tan^{-1}(x+\sqrt{1+x^2})$

If we set

$u=(x+\sqrt{1+x^2})$

Then

$\displaystyle u'=1+\frac{2x}{2\sqrt{1+x^2}}$

$\displaystyle u'=1+\frac{x}{\sqrt{1+x^2}}$

Taking the derivative of y

$y'=3[tan^{-1}(x+\sqrt{1+x^2})]'$

Using the change of variables

$\displaystyle y'=3[tan^{-1}u]'=3\frac{u'}{1+u^2}$

$\displaystyle y'=3\frac{u'}{1+u^2}=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+(x+\sqrt{1+x^2})^2}$

Operating

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+x^2+2x\sqrt{1+x^2}+1+x^2}$

$\boxed{\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}}$

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2 years ago

there are 12 people on the basketball team. how many different 5-person starting lineups can be chosen?

Mrac [35]

If there are 5 specific spots and the order does matters then we would have:

11*9*8=792

Hope this helps!

7 0

3 years ago

Select the correct row in the table.

Dafna11 [192]

Answer:

(-4, 0)

Step-by-step explanation:

The x-intercept is when y = 0

Since y = 0 at x = -4, that is the row which reveals the x - intercept of the function.

4 0

2 years ago