Question

A 4.50 kilogram block of wood at 20.0°C is uniformly heated using 90,000. joules of heat. What will be the resulting

Answer 1

Answer:

Final temperature, T2 = 31.11°C

Explanation:

Given the following data;

Mass = 4.5kg

Initial temperature = 20°C

Quantity of heat = 90000J

Specific heat capacity = 1,800. J/kg-°C

To find the final temperature;

Heat capacity is given by the formula;

$Q = mcdt$

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Making dt the subject of formula, we have;

$dt = \frac {Q}{mc}$

Substituting into the equation, we have;

$dt = \frac {90000}{4.5*1800}$

$dt = \frac {90000}{8100}$

dt = 11.11°C

Now, to find the final temperature T2;

But, dt = T2 - T1

Substituting into the equation, we have;

T2 = 11.11 + 20

Final temperature, T2 = 31.11°C