Dacia wants to know how to determine the polar coordinate θ. What should Katarina tell Dacia?
1 answer:
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This question is incomplete, the complete question is;
A beam of white light passes through a uniform thickness of air. If the intensity of the scattered light in the middle of the green part of the visible spectrum (λ=520nm) is I, find the intensity (in terms of I) of scattered light
a) In the middle of the red part of the spectrum (λ= 665 nm)
b) In the middle of the violet part of the spectrum (λ = 420 nm)
Answer:
a) the intensity of scattered light ( in terms of ) In the middle of the red part of the spectrum is 0.3739
b) the intensity of scattered light ( in terms of ) In the middle of the violet part of the spectrum is 2.3497
Explanation:
Given the data in the question,
the visible spectrum (λ=520nm) =
we know that; intensity of scattered light is proportional to 1 / λ⁴
∝ ( 1 / λ⁴ )
so
a)
/
= ( λ / λ
)⁴
As the middle of the green part of the visible spectrum λ is 520nm and middle of the red part of the spectrum λ is 665 nm
we substitute
/
= ( 520 / 665 )⁴
/
= ( 0.781954887 )⁴
/
= 0.3739
= 0.3739
{ in terms of
}
Therefore, the intensity of scattered light ( in terms of ) In the middle of the red part of the spectrum is 0.3739
b)
/
= ( λ / λ
)⁴
As the middle of the green part of the visible spectrum λ is 520nm and middle of the red part of the spectrum λ is 420 nm
we substitute
/
= ( 520 / 420 )⁴
/
= ( 1.238095 )⁴
/
= 2.3497
= 2.3497
{ in terms of
}
Therefore, the intensity of scattered light ( in terms of ) In the middle of the violet part of the spectrum is 2.3497
By using Ohm's law, we can calculate the resistance of the wire. Ohm's law states that:
where V is the potential difference across the conductor, I is the current and R the resistance. Rearranging the equation, we get
Now we can use the following equation to calculate the length of the wire:
(1)
where
is the resistivity of the material
L is the length of the conductor
A is its cross-sectional area
In this problem, we have a wire of copper, with resistivity
. The radius of the wire is half the diameter:
And the cross-sectional area is
So now we can rearrange eq.(1) to calculate the length of the wire:
where V is the potential difference across the conductor, I is the current and R the resistance. Rearranging the equation, we get
Now we can use the following equation to calculate the length of the wire:
where
L is the length of the conductor
A is its cross-sectional area
In this problem, we have a wire of copper, with resistivity
And the cross-sectional area is
So now we can rearrange eq.(1) to calculate the length of the wire: