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3 years ago

Can someone help me with this? thx :)

Mathematics

2 answers:

GrogVix [38]3 years ago

8 0

Answer:

Table 1 is not a function because there are two y-values with the same x-values. Remember... y values can repeat but x values cannot repeat when their corresponding y values are different.

Table 2 is a function.

You would need to omit either (3,7) or (3,-2).

Please vote brainliest! Hope this helps, have a nice day.

svet-max [94.6K]3 years ago

3 0

Answer:

table 1 not function

table 2 function

for last q its 3, -2

Step-by-step explanation:

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Help please. (Simple question)

vladimir1956 [14]

Both missing angles are 45°

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3 years ago

Find the area of a plane figure bounded by lines

natulia [17]

Answer: 4.5

<u>Step-by-step explanation:</u>

First, find the points of intersection by solving the system.

y = x² + 2x + 4

y = x + 6

Solve by substitution:

x² + 2x + 4 = x + 6 ⇒ x² + x - 2 = 0 ⇒ (x + 2)(x - 1) = 0 ⇒ x = -2, x = 1

Now, integrate from x = -2 to x = 1

$\int\limits^1_2 {(x+6)-(x^{2}+2x+4) } \,$ <em>the bottom of the integral is -2 </em>

= $\int\limits^1_2 {x+6-x^{2}-2x-4 } \,$

= $\int\limits^1_2 {-x^{2}-x+2 } \,$

= $\frac{-x^{3}}{3} - \frac{x^{2}}{2}+2x\int\limits^1_2 {} \,$

= $(\frac{-1^{3}}{3} - \frac{1^{2}}{2}+2(1)) - (\frac{-(-2)^{3}}{3} - \frac{(-2)^{2}}{2}+2(-2))$

= $(\frac{-1}{3} - \frac{1}{2} +2) - (\frac{8}{3} -\frac{4}{2} -4)$

= $\frac{-9}{3} + \frac{3}{2} +6$

= -3 + 1.5 + 6

= 4.5

3 0

3 years ago

Use the properties of exponents to write an equivalent expression that is a product of unique

jolli1 [7]

Ummm I just need to answer questions sorry!!!

5 0

3 years ago

Somebody help me please i will mark you the brainliest

Reptile [31]

I’m 100% sure it’s the 3rd one :)

5 0

3 years ago

Read 2 more answers

FIND THE SUM OF 20 TERMS OF THE ARITHMETIC SERIES IN WHICH 3rd TERM IS 7 AND 7th TERM IS 2 MORE THAN THREE TIMES ITS 3rd TERM

algol13

Answer:

740

Step-by-step explanation:

The n th term of an arithmetic series is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then

a₁ + 2d = 7 → (1)

a₁ + 6d = 23 → (2)

Subtract (1) from (2) term by term

4d = 16 ( divide both sides by 4 )

d = 4

Substitute d = 4 into (1)

a₁ + 2(4) = 7

a₁ + 8 = 7 ( subtract 8 from both sides )

a₁ = - 1

The sum to n terms of an arithmetic series is

$S_{n}$ = $\frac{n}{2}$ [ 2a₁ + (n - 1)d ] , thus

$S_{20}$ = $\frac{20}{2}$ [ (2 × - 1) + (19 × 4) ]

= 10(- 2 + 76) = 10 × 74 = 740

8 0

3 years ago