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3 years ago

8

Somebody help me please i will mark you the brainliest

2 answers:

Solnce55 [7]3 years ago

6 0

Answer:

I guess it's the 3rd one as well

Reptile [31]3 years ago

5 0

I’m 100% sure it’s the 3rd one :)

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Find the vertices and foci of the hyperbola with equation (x-5)^2/81 -(y-1)^2/144 = 1

vesna_86 [32]

Given the equation of an hyperbola in the form:
$\frac{(x-a)^2}{b^2}- \frac{(y-c)^2}{d^2}=1$
Then the focus of the hyperbola is $(\pm\sqrt {b^2+d^2},0)$
Compute like this:
$\sqrt{81+144}=15$
So the two focus points are $(\pm15,0)$
The vertices are given by the formula: $(\pm a,0)$
We deduce the two vertices of the given hyperbola: $(\pm9,0)$
since $\sqrt{81}=9$

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4 years ago

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Alenkasestr [34]

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Identify Variables

loris [4]

Step-by-step explanation:

<u>Substitute x = 12 and y = 4 into the equations:</u>

<u>1.</u>

$12 + 4 = 12$

Incorrect.

<u>2</u><u>.</u>

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Incorrect.

<u>3</u><u>.</u>

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<u>4.</u>

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Answer:

7 percent

Step-by-step explanation:

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