F(x)= 2x²+4x-6 and g(x)=2x-2, find each function
1. (f/g) (x) = f(x)÷g(x) = (2x²+4x-6)÷(2x-2)
First factor both top and bottom:
(2x-2)(x+3)÷(2x-2) = x+3
2. f(a + 2) = plug (a+2) in anywhere there is an x in f(x)=2x²+4x-6 -->
2(a+2)^2 +4(a+2)-6 = 2(a^2+4a+4)+4a+8-6, now distribute:
2a^2+8a+8+4a+2, combine like terms
2a^2+12a+10
3. g(a/2) = plug (a/2) in anywhere there's an x in g(x)=2x-2:
2(a/2)-2 = a-2
<h2>47/100</h2><h3></h3><h3>0.2 + x = 0.67</h3><h3>subtract 0.2 from both sides</h3><h3>x = 0.47</h3>
Answer:
If this is solving for a hypotenuse, the answer is 8.
Step-by-step explanation:
a^2 + b^2 = c^2
6^2 b^2 = 10^2
36 + b^2 = 100
100 - 36 = 64
The square root of 64 is 8.
Answer:
The answer is A. 
Step-by-step explanation:
Answer:
answer is <u>6.8 m</u>
Step-by-step explanation:
√46.24 m
= 6.8 m
