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2 years ago

15

Estimate the number of pints in 445 fluid ounces. Explain your work.

1 answer:

nekit [7.7K]2 years ago

8 0

Answer:

I dont know im 4 years old and i have a man on my back

Step-by-step explanation:

Hi im memememem

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Dad is 4 times as old as his son Jim. In 10 years, Dad's age will be 20 years more than twice Jim's age. How old is Jim? 10 year

mezya [45]

Jim is currently 15 years old!!

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3 years ago

What is the difference between rates and proportions???

frez [133]

A rate often involves time: e. g., 33 feet per second; also, we are finding the ratio of one type of measurement with respect to another: distance and time.

A proportion is often the ratio of different measures of the same thing:

e. g. 5 apples
------------
7 apples

6 0

3 years ago

The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,

uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

$\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right)$ .

We need to solve it and obtain an expression for $P(t)$ in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

$\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right)$ .

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that $k=0.04$ and $K=500$ and the initial condition $P(0)=100$ .

Notice that this equation is separable, then

$\frac{dP}{P(1-P/K)} = kdt$ .

Now, intagrating in both sides of the equation

$\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C$ .

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

$\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}$ .

So,

$\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|$ .

We have obtained that:

$-\ln\left| \frac{K-P}{P}\right| = kt +C$

which is equivalent to

$\ln\left| \frac{K-P}{P}\right|= -kt -C$

Taking exponentials in both hands:

$\left| \frac{K-P}{P}\right| = e^{-kt -C}$

Hence,

$\frac{K-P(t)}{P(t)} = Ae^{-kt}$ .

The next step is to substitute the given values in the statement of the problem:

$\frac{500-P(t)}{P(t)} = Ae^{-0.04t}$ .

We calculate the value of $A$ using the initial condition $P(0)=100$ , substituting $t=0$ :

$\frac{500-100}{100} = A}$ and $A=4$ .

So,

$\frac{500-P(t)}{P(t)} = 4e^{-0.04t}$ .

Finally, as we want the value of $t$ such that $P(t)=200$ , we substitute this last value into the above equation. Thus,

$\frac{500-200}{200} = 4e^{-0.04t}$ .

This is equivalent to $\frac{3}{8} = e^{-0.04t}$ . Taking logarithms we get $\ln\frac{3}{8} = -0.04t$ . Then,

$t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325$ .

So, the population of rats will be 200 after 25 months.

6 0

3 years ago

Omari and daisy live on my he same street as their school. Omari lives 3 1/2 blocks west of the school and daisy lives 3 1/4 blo

OLEGan [10]

Omari (3 1/2)___________(0)school____________(3 1/4)daisy

3 1/2 + 3 1/4 = 6 + (1/2 + 1/4) = 6 + (2/4 + 1/4) = 6 3/4 blocks apart <==

5 0

3 years ago

What is the y-intercept for the function f(x)=2•5+4<br> A)y=2<br> B)y=4<br> C)y=6<br> D)y=14

Oksi-84 [34.3K]

Answer:

D) y=14

Step-by-step explanation:

2×5+4

Two multipled by five then add 4 is 14

5 0

3 years ago