A jump discontinuity occurs when the limits as x approaches a number from the left and right are not equal. Basically, the graph "jumps" from one number to another at that x value.
A point discontinuity occurs when limits as x approaches a number from the left and right are equal, but the actual value of f(x) at x is not equal to the limit. Basically, a point is missing and there is a "hole" in the graph at that x value.
Looking at your graph, you can see that at x=0, the graph "jumps" from a value of 2 as the graph approaches x=0 from the left to a value of 1 as the graph approaches x=0 from the right. That means there is a jump discontinuity at x=0.
You can also see that there is a "hole" in the graph at x=-2 and x=8 as seen by the open circle. There is no hole at x=3 because the circle is filled in. That means there is a point discontinuity at x=-2 and x=8.
Your answer is B) jump discontinuity at x=0; point discontinuities at x=-2 and x=8.
A integer that is divisible by 2 can be -2,-4,-6,4,2,6 or something else, but these are simpler.
Answer:
f(3) = -11
Step-by-step explanation:
f(3) means you sub the value that is inside into x
f(3) = -3(3) - 2
= -9 - 2
= -11
Answer:
The equation of line in the form of Ax + By = C is: 
Step-by-step explanation:
We need to find the equation of line, with the given slope passes through the given point.
Slope m = -4
Point: (-2,-9)
We need to find slope and y-intercept of the line.
The slope of line is given m = -4
Now, we need to find the y-intercept
Using the point (-2,-9) and slope m = -4, we can find y-intercept
The formula used will be: 
Putting values of: y= -9, x =-2 and m = -4
So, y-intercept b = -17
Now, the equation of required line having slope m = -4 and y-intercept b = -17 is:
Writing equation in required form i.e. of Ax + By = C
So, the equation of line in the form of Ax + By = C is:
