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andrew-mc [135]
3 years ago
7

8-7x+10-5y+3 identify the constants

Mathematics
1 answer:
AlladinOne [14]3 years ago
5 0
Constants are the numbers with the letters by them so they would be -7x and -5y :)
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Hi what is the answer for this?
saw5 [17]
This is a common factor problem.

Pencils come in a pack of 12
Erasers come in a pack of 10

First, break the number into their prime factors(the idea is that we will break the number down into its smallest multiples, which are prime numbers):
10 = 2 * 5
12 = 2 * 2 *3

So now we take the unique multiples of each number, and when we multiply them together, we will get the smallest number that both 10 and 12 can be divided into(this is what the problem is asking for)
We have (2*2*3) that comes from 12, and the only unique number that comes from the 10 is (5)
So now, we multiply:
2*2*3*5=60
However, this isn't exactly out answer. Now we have to divide our answer by the number of each this in the pack to know how many packs to buy.
60/12=5 packs of pencils
60/10= 6 packs of erasers

I hope this helps. Let me know if you have any questions!!
5 0
3 years ago
Read 2 more answers
valerie has 8 blue markers and 10 green markers. she has 2 times as many red markers as blue and green markers combined. which d
aleksley [76]
This question means the than (8 + 10) x 2 = red markers. She has 32 red markers, 8 blue markers, and 10 green markers. If you add them all up, you get 50 markers.
7 0
3 years ago
The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand
NNADVOKAT [17]

Answer with Step-by-step explanation:

We are given that

The probability that an American CEO can transact business in  foreign language=0.20

The probability than an American CEO can not transact business in foreign language=1-0.20=0.80

Total number of American CEOs  chosen=12

a. The probability that none can transact business in a foreign language=12C_0(0.20)^0(0.80)^{12}

Using binomial theorem nC_r(1-p)^{n-r}p^r

The probability that none can transact business in a foreign language=\frac{12!}{0!(12-0)!}(0.8)^{12}=(0.8)^{12}

b.The probability that at least two can transact business in a foreign language=1-P(x=0)-p(x=1)=1-((0.8)^{12}+12C_1(0.8)^{11}(0.2))=1-((0.8)^{12}+12(0.8)^{11}}(0.2))

c.The probability that all 12 can transact business in a foreign language=12C_{12}(0.8)^0(0.2)^{12}

The probability that all 12 can transact business in a foreign language=\frac{12!}{12!}(0.2)^{12}=(0.2)^{12}

5 0
3 years ago
Please help will mark brainly
Slav-nsk [51]

the answer is B because

2 2/3 = 8/3

8/3 x 3 = 24/3

24/3 = 8

I hope this helps

4 0
3 years ago
Read 2 more answers
How many radians is 234°?<br> Give the exact answer in simplest form.
prohojiy [21]

Answer:

4.082 radians

Step-by-step explanation:

Here we want to convert 234° into radians.

To do it, we use the fact that pi radians is equal to 180°

Then we can write two equations:

x radians = 234°

3.14 radians  = 180°

Where we want to find the value of x, which is the equivalent in radians to 234°.

Now we can take the quotient of these two equations to get:

( x radians)/(3.14 radians) = (234°/180°)

Solving this for x, we get:

x radians = (234°/180°)*(3.14 radians) = 4.082 radians.

3 0
3 years ago
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