All categories

3 years ago

What is an integer that is divisible by 2

Mathematics

1 answer:

Ilia_Sergeevich [38]3 years ago

3 0

A integer that is divisible by 2 can be -2,-4,-6,4,2,6 or something else, but these are simpler.

You might be interested in

The Distributive Property of 7 x 1,214

Nataly_w [17]

(8,498)HOPE IT HELPS!

7 0

3 years ago

Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

6 0

3 years ago

[this is urgent]Based on the triangle below, JK Is Included between angles:

Afina-wow [57]

Answer:

J and L

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What's the value of x? Enter your answer in the box.<br> x = {}

Pani-rosa [81]

All three angles on a triangle always equal 180°.

Example: 100°+40°+40°=180°

102+39=141°

180-141=39°

x = 39°

3 0

2 years ago

Read 2 more answers

Sports a pennant for the sports teams at lincoln high school is in the shape of an isosceles triangle. if the measure of the ver

PIT_PIT [208]

The base angles are congruent because it's an isosceles triangle the base angles would both equal 81

5 0

3 years ago