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goldenfox [79]
3 years ago
14

What is an integer that is divisible by 2

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
3 0
A integer that is divisible by 2 can be -2,-4,-6,4,2,6 or something else, but these are simpler.
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Your friend attempted to factor an expression as shown. Find the error in your friends work. Then factor the expression correctl
loris [4]

Answer:

Third step is incorrect. The correct factored form is (x-1)(2x-5).

Step-by-step explanation:

The given expression is

2x^2-7x+5

We need to find the factored form of this expression.

Step 1: Given

2x^2-7x+5

Step 2: Splitting the middle term method, the middle term can be written as (-5x-2x).

2x^2-5x-2x+5

(2x^2-5x)+(-2x+5)

Step 3: Taking out common factors from each parenthesis.

x(2x-5)-1(2x-5)

Step 4: Taking out common factors.

(x-1)(2x-5)

Therefore, the third step is incorrect. The correct factored form is (x-1)(2x-5).

3 0
3 years ago
Describe one way in which the usage of vertex-edge graphs apply to you
LuckyWell [14K]

Answer:

you will be able to create and representations the vertex - edge graphs.

5 0
3 years ago
which of the following represents the area of a rectangle whose length is 5x-3 and whose width is x+7​
Neko [114]

Answer:

The answer is 5x^2+32x-21

Step-by-step explanation:

To find the area of a rectangle, you have to multiply the length by the width. Then, you will get the equation of (5x-3)(x+7). Then, multiply these two together, therefore getting 5x^2+32x-21.

5 0
3 years ago
PLSSSSSSSSSS HELPPPPPP MEEEEEEE, WILL RATE YOU BRAINLIEST!!!!!!!!!!!!!!
Artemon [7]
The lateral area of the prism is given by:
LA=[area of the two triangles]+[area of the lateral rectangles]
hypotenuse of the triangle will be given by Pythagorean:
c^2=a^2+b^2
c^2=6^2+4^2
c^2=52
c=sqrt52
c=7.211'
thus the lateral area will be:
L.A=2[1/2*4*6]+[6*8]+[8*7.211]
L.A=24+48+57.69
L.A=129.69 in^2

The total are will be given by:
T.A=L.A+base area
base area=length*width
=4*8
=32 in^2
thus;
T.A=32+129.69
T.A=161.69 in^2

Hope this helps:) plz mark brainiest i would really apperciate it
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5 0
3 years ago
Plz help, The graph of y = f(x) is shown below. What are all of the real solutions of f(x) = 0?
8_murik_8 [283]

Answer:

The real solutions of f(x)=0 are: 0, 2, 5, 6

Step-by-step explanation:

We are given:

The graph of y = f(x)

We need to find all of the real solutions of f(x) = 0?

By looking at the graph we need to find the values of y when x =0

Looking at the graph, when x=0 we get

0, 2,5 and 6

So, the real solutions of f(x)=0 are: 0, 2, 5, 6

I am attaching the figure, that determines the answers.

8 0
3 years ago
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