Answer:
import java.util.*;
public class work {
// function for counting unique character
public static int numUnique(String input) {
boolean[] list = new boolean[Character.MAX_VALUE];
for (int i = 0; i < input.length(); i++) {
list[input.charAt(i)] = true;
}
int count = 0;
for (int i = 0; i <list.length; i++) {
if (list[i] == true){
count++;
}
}
return count;
}
public static void main(String args[])
{
List<String>list=new ArrayList<>(); // creatng array list of type string
list.add("abcdef");
list.add("aaabcd");
list.add("bccddee");
list.add("abcddd");
list.add("a");
for(String str:list)
{
// for printing the results
System.out.println("given string : "+ str+" , number of unique values :"+numUnique(str));
}
}
}
Explanation:
it's either C or D I am pretty sure that the answer is D
Answer:
have you told anyone about it? like a teacher or something?
Explanation:
I think it's just a glitch
Answer:
A 1 MB digital file needs 0.23 seconds to transfer over a channel with bandwidth 10 MHz and SNR 10 dB.
Explanation:
We can calculate the channel capacity using Shannon's Capacity formula:
C = B + log₂ (1 + SNR)
Where C = Channel Capacity
B = Bandwidth of the Channel
SNR = Signal to Noise Ratio
We are given SNR in dB so we need to convert it into a ratio.
= 10log₁₀ (SNR)
10 = 10log₁₀ (SNR)
1 = log₁₀ (SNR)
SNR = 10¹
SNR = 10
So, using Shannon Channel Capacity formula:
C = 10 x 10⁶ log₂ (1 + 10)
C = 34.5 MHz
Total amount of time required to transmit a 1MB file:
1MB = 1 x 8 Mbytes = 8Mb
C = 34.5 MHz = 34.5 Mb/s
Time required = 8Mb/34.5Mb/s = 0.23 seconds
A 1 MB digital file needs 0.23 seconds to transfer over a channel with bandwidth 10 MHz and SNR 10 dB.
Answer:
The correct answer for the given question is an option(b) i.e "interdomain routing".
Explanation:
The Interdomain Routing algorithm protocol works between the domains. The protocol which is used in the interdomain routing is called as exterior gateway protocol. In the interdomain routing protocols works between the autonomous systems, it means they are taking place in the autonomous networks.
- Intradomain routing works within the domain. They are not works between the autonomous systems so the option(a) is incorrect.
- Out-of-domain are neither work in within or between the system so option(d) is incorrect.
