Explanation:
A hub is used to send the message from one port to other ports.It does not know the specific address of the destination where the message needs to send.it works on Physical layer of the OSI model(layer 1).
A switch can handle data and it knows the specific address of the destination.A switch works on the data link Layer of the OSI model(layer 2).
Hi! I have been troubleshooting and building PCs all my life and I find it very important to know the the internal core components of a PC and how they function that way when errors occur you can attempt to fix the problem.
Ex1: Lets say your BIOS identifies a problem with a RAM slot you would be able to know that your RAM slot is either shorted or there is a problem with the RAM stick you inserted.
Ex2: Now your monitor is flashing and turning colors randomly. You could make an inference that either your monitor is prongs are broken, your cable prongs could be bent, your cable might not be plugged in all the way, or your external or integrated GPU is toast.
Hope this might've showed you something
Aaron
Answer:
<em>C++</em>
///////////////////////////////////////////////////////////////////////////////////////////
#include <iostream>
using namespace std;
//////////////////////////////////////////////////////////////////
class QuadraticEquation {
int a, b, c;
public:
QuadraticEquation(int a, int b, int c) {
this->a = a;
this->b = b;
this->c = c;
}
////////////////////////////////////////
int getA() {
return a;
}
int getB() {
return b;
}
int getC() {
return c;
}
////////////////////////////////////////
// returns the discriminant, which is b2-4ac
int getDiscriminant() {
return (b*2)-(4*a*c);
}
int getRoot1() {
if (getDiscriminant() < 0)
return 0;
else {
// Please specify how to calculate the two roots.
return 1;
}
}
int getRoot2() {
if (getDiscriminant() < 0)
return 0;
else {
// Please specify how to calculate the two roots.
return -1;
}
}
};
//////////////////////////////////////////////////////////////////
int main() {
return 0;
}
Answer:
Option D is correct.
Explanation:
A high-level safety violation could be anticipated to have a serious or disastrous negative impact on organisational activities, organisational assets.
The effect of the violation on an organisation may be staggering, and sometimes unknown until the outcomes are achieved. It is strange that, owing to harmful or neglectful acts, the greatest incidents of compromise come from within the business ; it requires time for an organisation to recover.
Answer:
The solution code is written in Python 3:
- def modifyList(listNumber):
- posCount = 0
- negCount = 0
-
- for x in listNumber:
- if x > 0:
- posCount += 1
- else:
- negCount += 1
-
- if(posCount == len(listNumber)):
- listNumber.append(max(listNumber))
-
- if(negCount == len(listNumber)):
- listNumber.append(min(listNumber))
-
- print(listNumber)
-
- modifyList([-1,-99,-81])
- modifyList([1,99,8])
- modifyList([-1,99,-81])
Explanation:
The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).
To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).
If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).
If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.
At last we can print the listNumber (Line 17).
If we test our function using the three sets of input list, we shall get the following results:
[-1, -99, -81, -99]
[1, 99, 8, 99]
[-1, 99, -81]
