3 years ago

4 − 3x − 7 + 6 Please tell me... I NEED HELP FAST FOR MATH PPLSSSSSS

Mathematics

1 answer:

nydimaria [60]3 years ago

5 0

Answer:

-3x+3

Step-by-step explanation:

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3 years ago

Given f(x), find g(x) and h(x) such that f(x)=g(h(x)) and neither g(x) nor h(x) is solely x. f(x)=−3x+4⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√3+5

iVinArrow [24]

Answer:

$h(x)=-2x+4$

$g(x)=\sqrt[3]{x}-5$

Step-by-step explanation:

Consider the given function is

$f(x)=\sqrt[3]{-2x+4}-5$

It is given that $f(x)=g(h(x))$ and neither g(x) nor h(x) is solely x.

$f(x)=\sqrt[3]{(-2x+4)}-5$

Let $h(x)=-2x+4$ , then we get

$f(x)=g(h(x))=\sqrt[3]{h(x)}-5$

Substitute h(x)=x in the above function.

$g(x)=\sqrt[3]{x}-5$

Therefore, the required functions are $h(x)=-2x+4$ and $g(x)=\sqrt[3]{x}-5$ .

Check the solutions.

$g(h(x))=g(-2x+4)$ $[\because h(x)=-2x+4]$

$g(h(x))=\sqrt[3]{-2x+4}-5$ $[\because g(x)=\sqrt[3]{x}-5]$

$g(h(x))=f(x)$

Therefore, our solution is correct.

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'nine less than three times a number is negative twenty-one.'

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