Answer:
4845 combinations
Step-by-step explanation:
Whenever there is a selection of some elements from a certain group, there are several ways to do so. There are different combinations from the group which can be selected. The concept of combination means that there are certain number of elements to be selected from the group and there is no importance given to the order of the selection. The total number of students are 20, and 4 out of them have to be selected. It can be clearly seen that the order of selection does not matter, therefore the formula to be used is:
Combinations = 20C4 = (20*19*18*17)/(4*3*2*1) = 4845.
So the correct answer is 4845 combinations!!!
Answer:
$7.50
Step-by-step explanation:
You use inverse operations to evaluate the equation. You subtract 5 from 20, which is 15. Then you divide 15 by 2, which is 7.5.
The x coordinate of X and X' has to be the same. T<span>he coordinates of X is (4,5) so its distance to y=1 is 5 - 1 = 4. T</span>he distance from X' to y=1 must also be 4. T<span>he distance from -3 to 1 is 4. So, the answer for the given question above is (4,-3). I hope this helps.</span>
Theorem: If a function y = f(x) has a real root of b, then (x – b) is a factor of f(x).
As given in the problem, there are two roots: –2 and 1/2. The multiplicity of 1/2 is 2 meaning that the root 1/2 repeats twice. So the function f(x) can be written like this.
f(x) = k• (x – (–2))(x – 1/2)^2 = k•(x + 2)(x – 1/2)^2
We're supposed to find the coefficient k to complete the function.
Given that f(–3) = 5, we can plug –3 in for x and 5 in for f(x).
So 5 = k •(–3 + 2)(–3 – 1/2)^2
5 = k(–1)(–7/2)^2
5 = -k•49/4
Then 5 • 4/49 = -k
Or k = –20/49
So the function with the least degree is
f(x) = –20/49 (x + 2)(x – 1/2)^2.
