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solmaris [256]
3 years ago
14

Explain how the tangents of complementary angles are related.

Mathematics
1 answer:
dezoksy [38]3 years ago
4 0

Answer:

  tan(α) = 1/tan(90°-α)

Step-by-step explanation:

The tangent of one is the reciprocal of the tangent of the other.

__

In a right triangle, ...

  tan = opposite/adjacent

For the two complementary acute angles in such a triangle, opposite and adjacent are swapped. That is the tangent of one is the inverse of the tangent of the other. (That inverse is also known as the cotangent.)

  tan(α) = cot(90°-α) = 1/tan(90°-α)

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Answer:

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Step-by-step explanation:

So remember what I told you about earlier, lets look at that first one.

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Next we have a increase in 1 and a decrease by 17...then 12...then 7 in y. This isnt decreasing by a constant amount like a linear function. It doesnt seem like a obvious exponential decrease either, and it isnt reversing like a quadratic function does. I am going to use something called logarthms, which you don't even need to think about yet, just to make sure that it is not an exponent.  Althouhg the difference in the exponent was only 0.0018, it is a differnece.<u> So this must be a none of the above</u>, sicne none of the functions apply. (If this is incorrect, and it is exponential, then the test is wrong. While the method I used is something found in mid algebra 2, it is still a method of finding a exponent of a number.)

Now we finish up with a change in x of 1, and a change of y by...-11, -11, -11!

Well, what do you think this is, thinking back on what I have said so far.

It is a constant change of -11y and 1x. Remember, a CONSTANT CHANGE.

What do you think it is :)

If you cannot figure it out, let me know in comments.

<u>Hope this is helps you!</u>

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Step-by-step explanation:

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