Ask question

Ask question

All categories

3 years ago

14

How many rectangular prisms 8 inches long, 5 inches wide, and 2 inches high can fit into another rectangular prism that measures

16 inches long, 10 inches wide, and 10 inches high?

1 answer:

tangare [24]3 years ago

8 0

Answer:

20

Step-by-step explanation:

Volume of rectangular prism = length × width × height

Length = 8 inches

Width = 5 inches

Height = 2 inches

Volume of rectanglular prism = length × width × height

= 8 inches * 5 inches * 2 inches

= 80 inches ³

Dimensions of another rectangular prism:

Length = 16 inches

Width = 10 inches

Height = 10 inches

Volume of rectangular prism B = length × width × height

= 16 inches * 10 inches * 10 inches

= 1,600 inches ³

Number of prism A that fits into prism B = Volume of prism B ÷ volume of prism A

= 1,600 inches ³ ÷ 80 inches ³

= 20

Number of prism A that fits into prism B = 20

You might be interested in

|6x|+3=21 solve for X (absolute value)

Fudgin [204]

Answer:

$x=3\text{ or } x=-3$

Step-by-step explanation:

So we have the equation:

$|6x|+3=21$

First, subtract 3 from both sides:

$|6x|=18$

Definition of absolute value:

$6x=18\text{ or } 6x=-18$

Divide both sides by 6 for both equations:

$x=3\text{ or } x=-3$

And we're done!

6 0

3 years ago

Read 2 more answers

Francisco makes $11 per hour doing part time work on Saturdays. He spends $3 on transportation to and from work. The equation y

ludmilkaskok [199]

Answer:

x=4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

2(a³+b²+11)+1(3+a³+b+11)

Ann [662]

Answer:

$2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36$

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

$2(a^3+b^2+11)+1(3+a^3+b+11)$

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

$2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14$

Therefore, $2(a^3+b^2+11)+1(3+a^3+b+11)$ is equal to:

$2a^3+2b^2+22+a^3+b+14$

Now, combining like terms using the commutative property of addition, we get:

$=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36$

Therefore, the simplified form is $3a^3+2b^2+b+36$

8 0

3 years ago

Given: y" - 2y' = 6t + 5e^2t. Find the correct form to use for y_p if the equation is solved using Undetermined coefficients. Do

const2013 [10]

Answer:

$y_p=A+Bt+Ce^{2t}$

Step-by-step explanation:

Given: $y'' - 2y' = 6t + 5e^{2t}$ .

we need to find the correct form for $y_p$ if the equation is solve using undetermined coefficients.

A first order differential equation $\frac{\mathrm{d} y}{\mathrm{d} x}=f\left ( x,y \right )$ is said to be homogeneous if $f(tx,ty)=f(x,y)$ for all t.

Consider homogeneous equation $y''-2y'=0$

Let $y=e^{rt}$ be the solution .

We get $(r^2-2r)e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2-2r=0$ .

So, we get solution as $y_c=c_1+c_2e^{2t}$

As constant term and $e^{2t}$ are already in the R.H.S of equation

$y" - 2y' = 6t + 5e^{2t}$ , we can take $y_p$ as $y_p=A+Bt+Ce^{2t}$

6 0

3 years ago

HELP HELP HELP PLS PLS PLS

Sergio [31]

Answer:

In order of the paragraph:

3, isosceles, greater, 3 in

Step-by-step explanation:

The first drop box has to be 3 because if you add up two sides of a triangle, the sum has to be greater than the third side. If two sides are equal, the triangle is isosceles. The third side cannot be 1 since 1+1 is not greater than 3. So the third side must measure 3in.

4 0

3 years ago