Vertex<em> </em>is at 
<em>y-intercept</em> is 3.
The parabola <em>opens up</em>.
Step-by-step explanation:
The graph of the equation is hereby attached in the answer area.
Vertex is the point on the parabola where the graph crosses its axis of symmetry. The axis of symmetry here(
), is shown with the dotted line in the graph attached.
<em>y-intercept </em>is defined as the value of y where the graph crosses the y-axis. In other words, when
. Putting
And, the graph opens up as shown the graph figure as well. It is also evident from the co-efficient of
in the given equation
. Here, co-efficient of
So, vertex<em> </em>is at 
<em>y-intercept</em> is 3.
The parabola <em>opens up</em>.
Answer:

Step-by-step explanation:
cot(-11pi/6)=cot(-pi-5pi/6)= -cot(5pi/6)=cot(pi/6)=
≈1.73
Solve it by substitution. First let's rewrite the first equation (3x+4y=16) so we have y = something, then we'll substitue that in to the other equation.
3x+4y=16
4y=-3x+16
y=-3/4x+4
Now we can substitute this into the other equation.
8) C
9) A
10) B
11) C
Hope i could help
Answer:
height = 12 cm
base length = 4 cm
Step-by-step explanation:
area of a triangle
base length × height / 2
x = height
y = base length
x = y + 8
24 = y × (y + 8) / 2
48 = y × (y + 8) = y² + 8y
squared equation
y² + 8y - 48 = 0
solution
y = (-b ± sqrt(b² - 4ac))/(2a)
a = 1
b = 8
c = -48
y = (-8 ± sqrt(64 - 4×-48))/2 = (-8 ± sqrt(64 + 192))/2 =
= (-8 ± sqrt(256))/2 = (-8 ± 16)/2 = -4 ± 8
y1 = -4 + 8 = 4 cm
y2 = -4 - 8 = -12
but a negative base length did not make any sense, so only y = 4 remains.
x = y + 8 = 4 + 8 = 12 cm