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VashaNatasha [74]
3 years ago
10

Question

Mathematics
1 answer:
Rus_ich [418]3 years ago
8 0

9514 1404 393

Answer:

  S = 4.5π ≈ 14.14 units

Step-by-step explanation:

The arc length is given by ...

  s = rθ . . . . . r = radius; θ = central angle in radians

The angle 135° is ...

 135° = 135°(π/180°) = 3π/4 radians

The arc of interest has length ...

  s = 6×3π/4 = 9/2π ≈ 14.14 . . . units

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On Saturday, Tom is paid $12.75 an hour plus a Saturday bonus of $25. Sara is paid $11.75 an hour plus a bonus of $29. For how l
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They must work for more than 4 hours for Tom's bonus to be greater than Sara's

Step-by-step explanation:

Tom pay: 12.75x+25

Sara pay: 11.75x+29

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Simplify the expression. 3x - (2x + 4) + 5
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Read 2 more answers
According to the U.S. Census Bureau, 42% of men who worked at home were college graduates. In a sample of 480 women who worked a
Likurg_2 [28]

Answer:

1) 0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315

The point estimate for the proportion of college graduates among women who work at home is 0.327

2) 0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315

0.327 + 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.339

The 80% confidence interval is given by (0.315; 0.339)

Step-by-step explanation:

For this case we have the following info given:

X = 157 represent the women who worked at home who were college graduates

n = 480 the sample size selected

Part 1

In order to find the proportion of college graduates among women who work at home and we can use the following formula:

\hat p=\frac{X}{n} = \frac{157}{480}= 0.327

The point estimate for the proportion of college graduates among women who work at home is 0.327

Part 2

Construct an 80% confidence interval for the proportion of women who work at home who are college graduates. Round the answer to three decimal places. An 80% confidence interval for the proportion of women who work at home Is < p <

The confidence interval for the true proportion would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 80% confidence interval the value for the significance is\alpha=1-0.8=0.2 and \alpha/2=0.1, the critical value would be given by:

z_{\alpha/2}=0.539

And replacing we goot:

0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315

0.327 + 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.339

The 80% confidence interval is given by (0.315; 0.339)

6 0
3 years ago
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