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kiruha [24]
3 years ago
10

A group consists of 10 kids and 2 adults. On a hike, they must form a line with an adult at the front and an adult at the back.

How many ways are there to form the line?a. 4.9!b. 2.99!c. 11!d. 11!/2
Computers and Technology
1 answer:
blsea [12.9K]3 years ago
6 0

Answer:

b. 2.9!

Explanation:

There are is a mistake in the question.

Suppose the group consist of 10 kids and 2 adults, the number of ways in which they can form the line is:

= 2! 10!

= 2× 1× 10!

= 2.10!

But since that is not in the given option.

Let assume that the group consists of 9 kids and 2 adults, the number of ways in which they can form the line is:

No of ways the kids can be permutated =  9 ways

No of ways the adult can be permutated  = two ways.

Thus; the number of ways in which they can form the line = 2! 9!

= 2 × 1× 9!

= 2.9!

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A CPU has just been powered on and it immediately executes a machine code instruction. What is the most likely type of instructi
adell [148]

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2 years ago
Programming challenge description: Write a program that, given two binary numbers represented as strings, prints their sum in bi
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Answer:

The program to this question can be given as:

Program:

#include<iostream>  //include header file

using namespace std;  

string add(string a, string b)  //define add function

{       //declare variable  

   string result = "";  

   int sum = 0,k,l;      

   cahr x;    

   k= a.size() - 1;

   l = b.size() - 1;  

   while (k>= 0 || l>= 0 || sum == 1) //loop

   {

   //addition 

       sum= sum+ ((k >= 0)? a[k] - '0': 0);  

       sum= sum+ ((l >= 0)? b[l] - '0': 0);

        x=sum%2;

      result=(x+'0') +result;

  // Compute carry

       sum =sum/ 2;  

       // Move to next digits  

       k--;  

       l--;  

   }  

   return result; //return value

}

int main()  //main method  

{  

   string a,b;  //string variable

   cout<<"Enter first binary digit: ";  //message.

   cin>>a;     //input from user

   cout<<"Enter Second binary digit: ";  //message.

   cin>>b;     //input from user

   cout <<"Addition :"<<add(a, b)<<endl; //print addition

   return 0;  

}

Output:

Enter first binary digit: 1101

Enter Second binary digit: 100

Addition :10001

Explanation:

In the above c++ program first, we include the header file. Then we define the add function in the add function we add two binary digits by passing value as arguments. In this function, we define a variable that is used on the addition of binary numbers. In this function we define the loop in the loop we check if two binary number is 1 then it will print 0 and pass 1 as the carry. after performing addition it will return value. In the main function, we take two binary numbers from the user and pass the value to the function and print function return value.

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3 years ago
This program will store roster and rating information for a soccer team. Coaches rate players during tryouts to ensure a balance
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Answer:

Question Options :

(1) Prompt the user to input five pairs of numbers: A player’s jersey number (0 – 99) and the player’s rating (1 – 9). Store the jersey numbers in one int array and the ratings in another int array. Output these array(i.e., output the roster).

(2) Implement a menu of options for a user to modify the roster. Each option is represented by a single character. The program initially outputs the menu, and outputs the menu after a user chooses an option. The program ends when the user chooses the option to Quit. For this step, the other options do nothing. (2 pt)

(3) Implement the “Output roster” menu option. (1 pt)

(4) Implement the “Add player” menu option. Prompt the user for a new player’s jersey number and rating. Append the values to the two arrays. (1 pt)

(5) Implement the “Delete player” menu option. Prompt the user for a player’s jersey number. Remove the player from the roster (delete the jersey number and rating). (2 pts)

(6) Implement the “Update player rating” menu option. Prompt the user for a player’s jersey number. Prompt again for a new rating for the player, and then change that player’s rating. (1 pt)

(7) Implement the “Output players above a rating” menu option. Prompt the user for a rating. Print the jersey number and rating for all players with ratings above the entered value. (2 pts)

/******************************************************************************

This program will store roster and rating information for a soccer team.

                             

*******************************************************************************/

#include <iostream>

#include <vector>

using namespace std;

int main() {

   vector< int> jerseyNumber;

   vector< int> rating;

   int temp;

   for (int i = 1; i <= 5; i++) {

       cout << "\nEnter player " << i << "'s jersey number: ";

       cin >> temp;

       if ((temp >= 0) && (temp <= 99)){

           jerseyNumber.push_back(temp);}

       cout << "Enter player " << i << "'s rating: ";

       cin >> temp;

       if ((temp >= 0) && (temp <= 9)){

       rating.push_back(temp);}

       cout << endl;

   } cout << endl;

   cout << "ROSTER" << endl;

   for (int i = 0; i < 5; i++)

cout << "Player " << i + 1 << " -- " << "Jersey number: " << jerseyNumber.at(i) << ", Rating: " << rating.at(i) << endl;

   char option;

   while (true) {

       cout << endl;

       cout << "MENU" << endl;

       cout << "a - Add player" << endl;

       cout << "d - Remove player" << endl;

       cout << "u - Update player rating" << endl;

       cout << "r - Output players above a rating" << endl;

       cout << "o - Output roster" << endl;

       cout << "q - Quit" << endl << endl;

       cout << "Choose an option: " << endl;

       cin >> option;

       switch (option) {

           case 'a':

           case 'A':

               cout << "Enter another player's jersey number: " << endl;

               cin >> temp;

               if ((temp >= 0) && (temp <= 99)){

                   jerseyNumber.push_back(temp);}

               cout << "Enter another player's rating: " << endl;

               cin >> temp;

               if ((temp >= 0) && (temp <= 9)){

                   rating.push_back(temp);}

               break;

           case 'd':

           case 'D':

               cout << "Enter a jersey number: ";

               cin >> temp;

               for (int i = 0; i < jerseyNumber.size(); i++) {

                   if (jerseyNumber.at(i) == temp) {

                       jerseyNumber.erase(jerseyNumber.begin() + i);

                       rating.erase(rating.begin() + i);

                       break; }

               } break;

           case 'u':

           case 'U':

               cout << "Enter a jersey number: ";

               cin >> temp;

               for (int i = 0; i < jerseyNumber.size(); i++) {

                   if (jerseyNumber.at(i) == temp) {

                       cout << "Enter a new rating " << "for player: ";

                       cin >> temp;

                       rating.at(i) = temp;

                       break; }

               } break;

           case 'r':

           case 'R':

               cout << "Enter a rating: ";

               cin >> temp;

               cout << "\nABOVE " << temp << endl;

               for (int i = 0; i < jerseyNumber.size(); i++)

                   if (rating.at(i) > temp)

               cout << "Player " << i + 1 << " -- " << "Jersey number: " << jerseyNumber.at(i)

               << ", Rating: " << rating.at(i) << endl;

               break;

           case 'o':

           case 'O':

               cout << "ROSTER" << endl;

               for (int i = 0; i < jerseyNumber.size(); i++)

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               break;

           case 'q':

               return 0;

               default: cout << "Invalid menu option." << " Try again." << endl;

       }

     }

   }

Explanation:

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