Answer: C. Live
Explanation:
A live acquisition is where data is retrieved from a digital device directly via its normal interface such as activating a computer and initiating executables. Doing so has a certain level of risk because data is highly likely to be modified by the operating system. The process becomes significantly more common likely with less available disk space to the point of completely impractical to image.
Solution :
int f(int x){
;
}*/
int f(
){
int stack[2] = {
};
;
;
;
R1 = R1 * C; /*R1 = 
*/
;
* R2; /* R0 = bx */
; /*R0 = 
*/
;
; /*R0 = a+bx+cx^2 */
![\text{R1 = stack[0];}](https://tex.z-dn.net/?f=%5Ctext%7BR1%20%3D%20stack%5B0%5D%3B%7D)
![\text{ R2 = stack[1];}](https://tex.z-dn.net/?f=%5Ctext%7B%20R2%20%3D%20stack%5B1%5D%3B%7D)
}
/*
int s=0;
{ 
;)
*/
AREA SumSquares, code, readWrite
ENTRY
;loop 
MOV r1, #0 ; s = 0
Loop 
;calculate i*i
;s = s+ i*i
, #1 ; i = i+1
,#10 ; test for end
Loop ; 
END
Answer:
the depth of the shaft,
the carrying load of the skip and the mass of the counterweight,
the approximate size of the winding drum,
the approximate height of the headgear and the sheave wheel
Answer:
G=(A^3 + B) * 4-c^2
To calculate G if A=3, b=4 and C=5
cobegin
p1: A^3 = 27
P2:C^2 =25
P3: p1 +B =31
P4:P3*4 =124
P5:P4-P2 =99
coend
Explanation:
One operation is performed at a time, and on the basis of priority as we have only one processor.
