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3 years ago

I just do not understand how to answer this questions (not a test brainly)

Mathematics

2 answers:

Rudik [331]3 years ago

7 0

Answer:

200

Step-by-step explanation:

80% bought a drink

30% bought a snack

30% is said to be 120 people

So 60% would be 240 (30%x2)

To find the remaining 20% we need to find out how much one part will be so:

120÷30 is 4

20x4=80

240+80= 320

320-120=200

correct me if I'm wrong

goblinko [34]3 years ago

6 0

Answer: その店はスナックよりも96杯多い飲み物を売った。

Step-by-step explanation:

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What is the volume of a gift box in the shape of a rectangular prism that is 3.5 inches high, 7 inches long, and 6 inches wide

ankoles [38]

Answer:

147 cubic inches

Step-by-step explanation:

volume of the prism is length x breadth x height

3.5 x 7 x 6=147

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3 years ago

HELP PLEASE!! HURRY!!!! NO SPAM!!!!!! Identify the solution set of the inequality 4|f + 6| ≤ −16 and the graph that represents i

blagie [28]

Answer: f=3

Step-by-step explanation:

The intervals means that angle f is between the quadrant 1.

where x+y=90

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3 years ago

120<br> -5<br><br><br> Integer hellp me

lord [1]

Answer: 115 is the answer

Step-by-step explanation:

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3 years ago

ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th

Misha Larkins [42]

Answer:

a. $P(E_1/A)=0.0789$

b. $P(E_2/A)=0.395$ \

c. $P(E_3/A)=0.526$

Step-by-step explanation:

Let $E_1,E_2,E_3$ are the events that denotes the good drive, medium drive and poor risk driver.

$P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20$

Let A be the event that denotes an accident.

$P(A/E_1)=0.01$

$P(A/E_2=0.03$

$P(A/E_3)=0.10$

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem, $P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}$

We have to find $P(E_1/A)$

Using the Bayes theorem

$P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}$

Substitute the values then we get

$P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}$

$P(E_1/A)=0.0789$

b.We have to find the probability Mr.Brophy is a medium driver

$P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395$

c.We have to find the probability Mr.Brophy is a poor driver

$P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526$

7 0

3 years ago

Rina is making a nut mixture to sell at the local farmers' market. She mixes 6 pounds of pecans with a nut mixture that is 70% p

Marat540 [252]

So the best way to do these is concentration1 (%) × volume1 = concentration2 × volume2
Or C1V1 + C2V2 = C3V3, where C1 = 100% (bc ALL pecans), V1 = 6 lbs, C2 = 70%, C3 = 82%:
100%×6 + 70%×v2 = 82%×(6+v2)
100%=1.00, 70%=.7, 82%=.82
note: if none is poured out then v3 = v1+v2
6 + .7v2 = .82 (6+v2)
6 + .7v2 = 4.92 + .82v2
6 + .7v2 -.7v2 = 4.92 + .82v2 -.7v2
6 = 4.92 + .12v2
6-4.92 = 4.92-4.92 + .12v2
1.08 = .12v2
.12v2/.12 = 1.08/.12
v2 = 9 lbs
that's only v2!!!

For the final poundage, we need v3:

v3 = 6 + v2 = 6 + 9 = 15 lbs

7 0

3 years ago