Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
Answer:


Step-by-step explanation:
1. The result should by a 2 digit number.
So, I fix a two digit number first, say 60.
Then, I multiplied it by some random integer, say 4 and got 240.
Now, 240 is my dividend and 4 is my divisor.
My division problem is:

2. The result should be a 3 digit number.
So, I fix a three digit number first, say 600.
Then, I multiplied it by some random integer, say 3 and got 1800.
Now, 1800 is my dividend and 3 is my divisor.
My division problem is:

Answer:
The variance of the given data is 106.9667
Step-by-step explanation:
The variance, S² of a sample is given by the expression;

Where:
= One of the observations
= The mean of the observations
n = Number in the sample = 6
The mean = Σ
/n = (26 + 32 + 29 + 16 + 45 + 19
)/6 = 167/6 = 27.833
Therefore, we have;
S² = ((26 - 27.833)²+(32 - 27.833)²+(29 - 27.833)²+(16 - 27.833)²+(45 - 27.833)²+(19 - 27.833)²)/(6 - 1) = 106.9667.
The answer to the question is
52b - 43