Answer:
-45
Step-by-step explanation:
hope this helps
Answer:
Triangle BDA
Step-by-step explanation:
Since triangle BDA seems to share congruent sides with triangle ACB they seem to be congruent
Formatted Options:
A. sin²A−cos²A
B. sin²A+cos²A
C. cos²A−sin²A
D. cosA−sinA
Answer:
C. cos²A−sin²A
Step-by-step explanation:
From the double angle formulas, we know that:
cos (A + B) = cosAcosB - sinAsinB
So, if B = A, then the above equation becomes;
cos(A + A) = cosAcosA - sinAsinA [i.e replacing B with A]
=>cos(2A) = (cosA)² - (sinA)²
=> cos(2A) = cos²A - sin²A
Therefore,
cos(2A) is equivalent to cos²A - sin²A
something noteworthy, the y-coordinate for each point is the same, 9⅛, that means is a horizontal line, over which the x-coordinates are at, so since it's a horizontal line, all we need to do is find, what's the distance between 
of course, let's firstly convert the mixed fraction to improper fraction and then check their difference.
![\bf \stackrel{mixed}{5\frac{7}{10}}\implies \cfrac{5\cdot 10+7}{10}\implies \stackrel{improper}{\cfrac{57}{10}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{2}{5}-\left[-\cfrac{57}{10} \right]\implies \cfrac{2}{5}+\cfrac{57}{10}\implies \stackrel{\textit{using the LCD of 10}}{\cfrac{(2)2+(1)57}{10}}\implies \cfrac{4+57}{10}\implies \cfrac{61}{10}\implies 6\frac{1}{10}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B5%5Cfrac%7B7%7D%7B10%7D%7D%5Cimplies%20%5Ccfrac%7B5%5Ccdot%2010%2B7%7D%7B10%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B57%7D%7B10%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B2%7D%7B5%7D-%5Cleft%5B-%5Ccfrac%7B57%7D%7B10%7D%20%5Cright%5D%5Cimplies%20%5Ccfrac%7B2%7D%7B5%7D%2B%5Ccfrac%7B57%7D%7B10%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%2010%7D%7D%7B%5Ccfrac%7B%282%292%2B%281%2957%7D%7B10%7D%7D%5Cimplies%20%5Ccfrac%7B4%2B57%7D%7B10%7D%5Cimplies%20%5Ccfrac%7B61%7D%7B10%7D%5Cimplies%206%5Cfrac%7B1%7D%7B10%7D)
The perimeter of the rectangle is P = (17.2x₊16.4).
Given that,
Length, l = 8.6x₊3
Width, b = 5.2
In the formula P=2l+2w, where l is the rectangle's length and w is its width, the perimeter P of a rectangle is determined. Using the formula A=l×w, where l is the length and w is the width, we can determine the area A of a rectangle.
We need to find the expression for the perimeter of the rectangle. The formula for the perimeter of the rectangle is given by :
P=2(l₊b)
Putting values of l and b in the above formula:
p = 2(8.6x ₊ 3 ₊ 5.2)
= 2(8.6x ₊ 8.2)
= 2(8.6x) ₊ 2(8.2)
= 17.2x ₊ 16.4
So, the required perimeter of the rectangle is 17.2x₊16.4.
Learn more about Area Perimeter here:
brainly.com/question/25292087
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