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3 years ago

9

Translate the sentence into an equation Eight times the sum of a number and 4 equals 6 use the variable c for the unknown number

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PLS HELP MEE

1 answer:

uranmaximum [27]3 years ago

7 0

Answer: 8(c+4) = 6
This should be right.

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1/10 of 200 tables is

LiRa [457]

Of means multiplication in mathematics

$\frac{1}{10} \times 200 = 20$

Hope that helps :)

7 0

3 years ago

Read 2 more answers

W(x) = 2x + 5; Find w(x + 2)

ivolga24 [154]

Solution:

w(x) = 2(x + 2) + 5

w(x) = 2x + 4 + 5

w(x) = 2x + 9

Best of Luck!

3 0

4 years ago

Based on the cumulative frequency histogram, determine the number of swimmers who swam between 200 and 249 yards. Determine the

Lostsunrise [7]

Answer:

$(a)\ 200 \to 249 =3$

$(b)\ 150 \to 199 = 0$

$(c)\ Total = 20$

Step-by-step explanation:

Given

See attachment for cumulative frequency histogram

Solving (a): Swimmers between 200yd and 249yd

To do this, we simply read the data from the 0 mark

From the histogram, we have:

$0 \to 249 = 15$

and

$0 \to 199 = 12$

So:

$200 \to 249 = 0 \to 249 - 0 \to 199$

This gives:

$200 \to 249 = 15-12$

$200 \to 249 =3$

Solving (b): Swimmers between 150yd and 199yd

To do this, we simply read the data from the 0 mark

From the histogram, we have:

$0 \to 149 = 12$

and

$0 \to 199 = 12$

So:

$150 \to 199 = 0 \to 199 - 0 \to 149$

This gives:

$150 \to 199 = 12-12$

$150 \to 199 = 0$

Solving (c): Total swimmers

To do this, we simply read the longest bar of the histogram

$Longest = 20$

Hence:

$Total = 20$

4 0

3 years ago

Jason rolls the die 14 times. What is the experimental probability that he will roll a 2

Vaselesa [24]

There’s 14 rolls. The probability he lands on a 2 would be 2/14. Once you simplify it it would give you a probability of 1/7

5 0

3 years ago

If x = a sin α, cos β, y = b sin α.sin β and z = c cos α then (x²/a²) + (y²/b²) + (z²/c²) = ?

Oduvanchick [21]

$\large\underline{\sf{Solution-}}$

<u>Given:</u>

$\rm \longmapsto x = a \sin \alpha \cos \beta$

$\rm \longmapsto y = b \sin \alpha \sin \beta$

$\rm \longmapsto z = c\cos \alpha$

Therefore:

$\rm \longmapsto \dfrac{x}{a} = \sin \alpha \cos \beta$

$\rm \longmapsto \dfrac{y}{b} = \sin \alpha \sin \beta$

$\rm \longmapsto \dfrac{z}{c} = \cos \alpha$

Now:

$\rm = \dfrac{ {x}^{2} }{ {a}^{2}} + \dfrac{ {y}^{2} }{ {b}^{2} } + \dfrac{ {z}^{2} }{ {c}^{2} }$

$\rm = { \sin}^{2} \alpha \cos^{2} \beta + { \sin}^{2} \alpha \sin^{2} \beta + { \cos}^{2} \alpha$

$\rm = { \sin}^{2} \alpha (\cos^{2} \beta + \sin^{2} \beta )+ { \cos}^{2} \alpha$

$\rm = { \sin}^{2} \alpha \cdot1+ { \cos}^{2} \alpha$

$\rm = { \sin}^{2} \alpha + { \cos}^{2} \alpha$

$\rm = 1$

<u>Therefore:</u>

$\rm \longmapsto\dfrac{ {x}^{2} }{ {a}^{2}} + \dfrac{ {y}^{2} }{ {b}^{2} } + \dfrac{ {z}^{2} }{ {c}^{2} } = 1$

5 0

3 years ago