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aliina [53]
3 years ago
7

Help me please asap due tomorrow​

Mathematics
1 answer:
slava [35]3 years ago
4 0

Answer: 87.5

Step-by-step explanation:

Triangle area = base * height / 2

25 * 7 = 175

175/ 2 = 87.5

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Please help me! And please explain how to solve this. Especially questions B, C, and E
kati45 [8]
A. radical 76 is8.6 so  false
B. 3 radical 10 is 9.4  true
C. 4 radical 2 is 5.6 so false
D. radical 29 is 5.3 so true
E. 2 radical 50 is 14.14 so false
5 0
3 years ago
What is the slope of D and E??
Mazyrski [523]

Answer:

-4 and 0

Step-by-step explanation:

Rise over Run would give us the slope.

In the first graph, It goes down 4 while it goes 1 to the right.

This means that -4/1 = -4.

The second graph does not go up or down, meaning 0, while it goes 1 to the right.

This means that 0/1 = 0.

4 0
2 years ago
2(3²+4²)=? <br><br><br><br><br> WHATS THE ANSWER
yulyashka [42]

Answer:

50

Step-by-step explanation:

P- Parenthesis

E- Exponents

M- Multiplication

D- Division

A- Addition

S- Subtraction

(3²+4²)

3*3= 9     4*4= 16     16+9= 25      2(25)      25*2= 50

Hope this helped! (ノ◕ヮ◕)ノ*:・゚✧

( ゚д゚)つ Bye

7 0
3 years ago
When the domain of a function has an infinite number of values, the range always has an infinite number of values. True or false
iragen [17]

Answer:

Thus, the statement is False!

Step-by-step explanation:

When the domain of a function has an infinite number of values, the range may not always have an infinite number of values.

For example:

Considering a function

f(x) = 5

Its domain is the set of all real numbers because it has an infinite number of possible domain values.

But, its range is a single number which is 5. Because the range of a constant function is a constant number.

Therefore, the statement ''When the domain of a function has an infinite number of values, the range always has an infinite number of values'' is FALSE.

Thus, the statement is False!

3 0
3 years ago
Needhdjdjdjdjdjdnhiskdjdjdjdjdjdjjshdjdjdjdjdjdjdjd<br><br>​
Lilit [14]

9514 1404 393

Answer:

  -(√2)/2

Step-by-step explanation:

The expression evaluated at n=a gives the indeterminate form 0/0, so L'Hopital's rule can be used to find the limit. The second expression comes from differentiating numerator and denominator. Then the form with n=a is no longer indeterminate.

  \displaystyle\lim_{n\to a}{\frac{\sqrt{2n}-\sqrt{3n-a}}{\sqrt{n}-\sqrt{a}}}=\lim_{n\to a}{\frac{\frac{2}{2\sqrt{2n}}-\frac{3}{2\sqrt{3n-a}}}{\frac{1}{2\sqrt{n}}-0}}\\\\=\sqrt{a}\left(\frac{2}{\sqrt{2a}}-\frac{3}{\sqrt{3a-a}}}\right)=\boxed{-\frac{1}{\sqrt{2}}}

5 0
3 years ago
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