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egoroff_w [7]
3 years ago
12

A frog is sitting exactly in the middle of a board that is five feet long. Every ten seconds he jumps one foot to the left or on

e foot to the right, at random. You want to use simulation to estimate the probability that he jumps off the board in sixty seconds or less. (For example, if he jumps LLRLRL, he is still on the board, on the left-most square. If he jumps LLRLL, he has jumped off the board in fifty seconds.)
Required:
Describe how you would use the digits of a random number table to carry out this simulation.
Mathematics
1 answer:
mart [117]3 years ago
4 0

Answer:

Since the Frog makes a Jump every 10 seconds

   ( using the digits on a random number table )

  • It will take 7 jumps with 2 jumps in reverse direction i.e. either left or right for the frog to be off the board in 60 seconds
  • it will take 3 jumps in similar direction as well to get the frog off the board
  • also 5 jumps with 1 jump in the opposite direction is what it will take to get the frog off the board as well within the time frame of 60 seconds

Step-by-step explanation:

A frog sitting exactly in the middle of a board which is 5ft long : frog is 2.5 ft from the edge of the board

every 10 seconds the frog jumps ; L or R

If he jumps ; LLRLRL ( still on Board on the left-most square )

if he jumps ; LLRLL ( He is off the Board in fifty seconds )

Since the Frog makes a Jump every 10 seconds

   ( using the digits on a random number table )

  • It will take 7 jumps with 2 jumps in reverse direction i.e. either left or right for the frog to be off the board in 60 seconds
  • it will take 3 jumps in similar direction as well to get the frog off the board
  • also 5 jumps with 1 jump in the opposite direction is what it will take to get the frog off the board as well within the time frame of 60 seconds
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Step-by-step explanation:

Given:

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Increase in population per year = 700

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Answer:

2. The area of the side walk is approximately 217 m²

3. The distance away from the sprinkler the water can spread is approximately 11 feet

4. The area of the rug is 49.6

Step-by-step explanation:

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The diameter of the flower bed = 20 meters

The width of the circular side walk, x = 3 meters

Therefore, the diameter of the outer edge of the side walk, D, is given as follows

D = d + 2·x (The width of the side walk is applied to both side of the circular diameter)

∴ D  = 20 + 2×3 = 26

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∴ The area of the side walk, A = π·D²/4 - π·d²/4

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3. Given that the area formed by the circular pattern, A = 379.94 ft.², we have;

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