5^(x+7)=(1/625)^(2x-13)
We move all terms to the left:
5^(x+7)-((1/625)^(2x-13))=0
Domain of the equation: 625)^(2x-13))!=0
x∈R
We add all the numbers together, and all the variables
5^(x+7)-((+1/625)^(2x-13))=0
We multiply all the terms by the denominator
(5^(x+7))*625)^(2x+1-13))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x-12))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x=0
not sure if this is right :/
Answer:
I'm not sure what you are asking for?
Step-by-step explanation:
The 5 in the tens place = 50, and the 5 in the hundreds place = 500.
To compare them (Are you asking me for the difference between them???), then, 500 - 50 = 450.
But, again, I'm not sure what you want.
The answers are
f
o
g
(
x
)
=
−
2
x
+
23
and
g
o
f
(
x
)
=
−
2
x
+
5
Explanation:
f
(
x
)
=
−
2
x
+
11
g
(
x
)
=
x
−
6
f
o
g
(
x
)
=
f
(
g
(
x
)
)
=
f
(
x
−
6
)
=
−
2
(
x
−
6
)
+
11
=
−
2
x
+
12
+
11
=
−
2
x
+
23
g
o
f
(
x
)
=
g
(
f
(
x
)
)
=
g
(
−
2
x
+
11
)
=
−
2
x
+
11
−
6
=
−
2
x
+
5
I think that the equations speak by themselves.
Of course,
f
o
g
(
x
)
≠
g
o
f
(
x
)
Answer:
This statement is false. The Algebraic expression x-2 represents two less than a number.
Based on the information given the chocolates stated on the label is 0.0042-ounce lighter.
Weight:
Using this formula
Chocolate weight=Current weight-Actual weight
Where:
Current weight=0.384
Actual weight=0.3798
Let plug in the formula
Chocolate weight=0.384-0.3798
Chocolate weight=0.0042 ounce
In conclusion, the chocolates stated on the label are 0.0042-ounce lighter.
