Ask question

Ask question

All categories

3 years ago

9

Expressed as a decimal, 3% is A 0.03 B 0.3 3.0 D 30.0

2 answers:

Gemiola [76]3 years ago

8 0

Answer:

0.03

Step-by-step explanation:

3% as a fraction is 3/100. as a decimal it is 0.03. notice when you read the decimal aloud, it is three one-hundredths, which is also the same read aloud in a fraction.

USPshnik [31]3 years ago

5 0

Answer:

A

Step-by-step explanation:

3/100=0.03

:))) Helps?

You might be interested in

Please help me I don’t have that much time

Salsk061 [2.6K]

Answer:

$a \geq 18$

Step-by-step explanation:

4 0

3 years ago

8) Jennifer has a collection of 1,600 coins. Of the coins, 40% are dated

Kitty [74]

<h3>Answer: 400 (choice A)</h3>

==============================================

Explanation:

40% + 35% = 75% of the coins were either made before 1940, or made from 1940 to 1980. In other words, 75% of the coins were minted before 1980. This leaves 100% - 75% = 25% of the coins to being minted after 1980.

25% of 1600 = 0.25*1600 = 400 coins were made after 1980

4 0

3 years ago

Gareth has just remodeled his kitchen and wants to buy one of two stand-alone freezers. Consider the following table, which

alexdok [17]

Answer:

A. Brand R will be $548.18 cheaper than Brand S. on Edge.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Dog food is sold in 7 pound bags. Sketch

Effectus [21]

Answer:

Continuous

Step-by-step explanation:

5 0

3 years ago

A worker at a landscape design center uses a machine to fill bags with potting soil. Assume that the quantity put in each bag fo

defon

Answer:

a) The expected value is given by:

$E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11$

The variance is given by:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333$

And the standard deviation is just the square root of the variance and we got:

$Sd(x) = \sqrt{0.3333}= 0.5774$

b) $P(X$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}, a \leq x \leq b$

And using this function we got:

$P(X$

c) $P(X>10.5)$

And using the complement rule and the cumulative distribution function we got:

$P(X>10.5)= 1-P(X$

Step-by-step explanation:

For this case we define the random variable X=quantity put in each bag , and we know that the distribution for X is given by:

$X \sim Unif (a= 10, b =12)$

Part a

The expected value is given by:

$E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11$

The variance is given by:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333$

And the standard deviation is just the square root of the variance and we got:

$Sd(x) = \sqrt{0.3333}= 0.5774$

Part b

For this case we want this probability:

$P(X$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}, a \leq x \leq b$

And using this function we got:

$P(X$

Part c

For this case we want this probability:

$P(X>10.5)$

And using the complement rule and the cumulative distribution function we got:

$P(X>10.5)= 1-P(X$

3 0

4 years ago