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Vikki [24]
3 years ago
8

A 1500kg car is travelling at v=30m/s. The cars kinetic energy is? *

Physics
1 answer:
Anuta_ua [19.1K]3 years ago
4 0

Hi there!

\large\boxed{\text{D. 675000J}}

Use the following formula to solve:

KE = 1/2mv², where:

KE = kinetic energy

m = mass (kg)

v = velocity (m/s)

Therefore:

KE = 1/2(1500)(30)²

KE = 1/2(1500)(900)

KE = 675000 J

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A 790N person runs up a flight of 40 stairs (.25m for each step) in 20 seconds, and then down 10 steps in 5 seconds. How much to
Romashka [77]

A person runs up 40 stairs and then come down 10 steps

So total stairs upwards is given as

N = 40 - 10 = 30

now here we will have total height reached

H = N\times h

H = 30 \times 0.25 = 7.5 m

Now total energy used or mechanical work done is

W = mgH

W = 790 \times 7.5 = 5925 J

Now the mechanical power is given as

P = \frac{W}{t}

P = \frac{5925}{20+ 5} = 237 W

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3 years ago
Before the internet was available people often search for jobs?
konstantin123 [22]

Answer:

do you mean how? if so

Explanation:people used newspapersand still kinda do back then they had posters up as they still do and newspapers

5 0
3 years ago
A thin, rectangular sheet of metal has mass M and sides of length a and b. Find the moment of inertia of this sheet about an axi
Lubov Fominskaja [6]

Answer:

The moment of inertia is I=\frac{M}{12} a^{2}

Explanation:

The moment of inertia is equal:

I=\int\limits^a_b {r^{2} } \, dm

If r is -\frac{a}{2}

and dm=\frac{M}{a} dr

I=\int\limits^a_b {r^{2}\frac{M}{a}  } \, dr\\a=\frac{a}{2} \\b=-\frac{a}{2}

I=\frac{M}{a} \int\limits^a_b {r^{2}  } \, dr\\\\I=\frac{M}{a} (\frac{M}{3} )_{b}^{a}\\  I=\frac{M}{3a} (\frac{a^{3} }{8} +\frac{a^{3} }{8} )\\I=\frac{M}{12} a^{2}

7 0
4 years ago
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True [87]
Seafloor<span> spreading is when the </span>sea floor<span> spreads apart. This occurs at Divergent</span>Boundaries<span>. At which type of </span>boundary is seafloor destroyed<span>? The </span>seafloor<span> is</span>destroyed<span> at a COnvergent </span>Boundary<span>.</span>
5 0
4 years ago
An object is in simple harmonic motion. Find an equation for the motion given that the frequency is 3⁄π and at time t = 0, y = 0
Delicious77 [7]

Answer: y(t)= 1/π^2 sin(6*π^2*t)

Explanation: In order to solve this problem we have to consider the general expression for a harmonic movement given by:

y(t)= A*sin (ω*t +φo) where ω is the angular frequency. A is the amplitude.

The data are: ν= 3π; y(t=0)=0 and y'(0)=6.

Firstly we know that 2πν=ω then ω=6*π^2

Then, we have y(0)=0=A*sin (6*π^2*0+φo)= A sin (φo)=0 then φo=0

Besides y'(t)=6*π^2*A*cos (6*π^2*t)

y'(0)=6=6*π^2*A*cos (6*π^2*0)

6=6*π^2*A then A= 1/π^2

Finally the equation is:

y(t)= 1/π^2 sin(6*π^2*t)

3 0
3 years ago
Read 2 more answers
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