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2 years ago

A factory makes 12 bikes in 3 hours.

Mathematics

1 answer:

zysi [14]2 years ago

6 0

12/3 = x/8

Cross multiply

3x = 96

Eliminate

3x/3 = 96/3

x = 32

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A group of students are meeting in the cafeteria. 70 students have already arrived. This is 35% of the group. How many are in th

sesenic [268]

There are 200 students in the group.

To find this, you divide 70 by 0.35 (35%). This will give you 200. To check this, multiply 200 by 0.35 and you will get 70. Thus making 200 the answer.

I hope this helps!

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2 years ago

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if a student has homework 72 days out of 100 what fraction and what percentage of days did the student not have homework?

neonofarm [45]

Answer:

The Student has 72% out of 100%

Step-by-step explanation:

Its the same thing but with fractions

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2 years ago

16. Choose the correct order of adjectives to fill in the blank. I bought a pair 1 point

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Answer:

candice

Step-by-step explanation:

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Hayden will attend a craft show the cost of admission ticket is eight dollars the cost of a raffle ticket for a handmade quilt a

ruslelena [56]

Answer: 7 tickets

Step-by-step explanation:

First you need to remove the cost of entrance from the $45 that Hayden has:

= 45 - 8

= $37

The $37 is the amount that is left for Hayden to be able to buy tickets for the raffle.

The tickets cost $5 each so the highest number of tickets that can be bought with $37 is:

= 37 / 5

= 7 tickets

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3 years ago

Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10

natka813 [3]

ANSWER

$( \frac{2}{3} , \frac{1}{5} )$

EXPLANATION

The first equation is

$\frac{1}{2} x - \frac{3}{4} y = \frac{11}{60} ...(1)$

The second equation is

$\frac{2}{5} x + \frac{1}{6} y = \frac{3}{10} ...(2)$

We want to eliminate y, so we multiply the first equation by

$\frac{4}{5}$

$\frac{4}{5} \times \frac{1}{2} x - \frac{4}{5} \times \frac{3}{4} y = \frac{11}{60} \times \frac{4}{5}$

$\frac{2}{5} x - \frac{3}{5} y = \frac{11}{75} ...(3)$

We now subtract equation (3) from (2)

$(\frac{2}{3} x - \frac{2}{3} x )+ ( \frac{1}{6} y - - \frac{3}{5}y ) =( \frac{3}{10} - \frac{11}{75} )$

$\frac{1}{6} y + \frac{3}{5}y =\frac{3}{10} - \frac{11}{75}$

$\frac{23}{30}y = \frac{23}{150}$

Multiply both sides by

$\frac{30}{23}$

$\implies \: \frac{30}{23} \times \frac{23}{30}y= \frac{23}{150} \times \frac{30}{23}$

$\implies \: y = \frac{1}{5}$

Substitute into the first equation to solve for x .

$\frac{1}{2} x - \frac{3}{4} \times \frac{1}{5} = \frac{11}{60}$

Multiply to obtain

$\frac{1}{2} x - \frac{3}{20} = \frac{11}{60}$

$\frac{1}{2} x = \frac{11}{60} + \frac{3}{20}$

$\frac{1}{2} x = \frac{1}{3}$

Multiply both sides by 2.

$2 \times \frac{1}{2} x =2 \times \frac{1}{3}$

$x = \frac{2}{3}$

The solution is

$( \frac{2}{3} , \frac{1}{5} )$

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2 years ago

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