Determine if they following is systems of equations?<br> y = 3x + 2<br> y = 7x -10

katrin2010 [14]

$\large\boxed{x=-\frac{7}{2}}$

To solve for $x$ , we need to isolate it on one side of the equation.

The most important part of this is knowing that whatever we do to one side of the equation, we must also do to the other.

Subtract 32 from both sides of the equation.

$\begin{aligned}32-32-6x&=53-32\\-6x&=21\end{aligned}$

Divide both sides of the equation by $-6$ .

$\begin{aligned}\frac{-6x}{-6}&=\frac{21}{-6}\\x&=\boxed{-\frac{7}{2}}\end{aligned}$

7 0

2 years ago

Read 2 more answers

Make a table with the domain of {2,3,4,5,6} and draw a graph of the absolute value function y = 2|x-4| + 3.

Jet001 [13]

Answer:

<h2>In the attachment.</h2>

Step-by-step explanation:

$|a|=\left\{\begin{array}{ccc}a&for\ a\geq0\\-a&for\ a$

Put each value of x from the set {2, 3, 4, 5, 6}

to the equation y = 2|x - 4| + 3:

x = 2 → y = 2|2 - 4| + 3 = 2|-2| + 3 = 2(2) + 3 = 4 + 3 = 7 → (2, 7)

x = 3 → y = 2|3 - 4| + 3 = 2|-1| + 3 = 2(1) + 3 = 2 + 3 = 5 → (3, 5)

x = 4 → y = 2|4 - 4| + 3 = 2|0| + 3 = 2(0) + 3 = 0 + 3 = 3 → (4, 3)

x = 5 → y = 2|5 - 4| + 3 = 2|1| + 3 = 2(1) + 3 = 2 + 3 = 5 → (5, 5)

x = 6 → y = 2|6 - 4| + 3 = 2|2| + 3 = 2(2) + 3 = 4 + 3 = 7 → (6, 7)

Mark the points in the coordinates system.

The domain is only five numbers, therefore the graph of this function is only five points.

5 0

3 years ago

Read 2 more answers

Find the value of c and YZ if Y is between X and Z.<br><br><br><br> XY=5.5, YZ=2c, XZ=8.9

andrey2020 [161]

Answer:

XZ = XY+ YZ

8.9=5.5+2c

2c= 8.9-5.5

2c=3.4

c=1.7

YZ = 2c=3.4

Step-by-step explanation:

6 0

3 years ago

Prove that if one solution for a quadratic equation of theform x2 + bx + c = 0 is rational (where b and c are rational),then the

Elenna [48]

Answer:

The other solution of the given equation x² + bx + c = 0 is also rational number.

Step-by-step explanation:

Here, given: ax² + bx + c = 0 is a quadratic equation

Also, one solution (r) of equation is RATIONAL.

To show: The other solution (s) is also RATIONAL

Now, here: as x² + bx + c = 0

Since r and s are the two given solutions, the given equation can be factorized as:

x² + bx + c = (x -r) (x - s)

Simplifying LHS, we get:

(x -r) (x - s) = x x - r (x) - s (x) + (r)(s)

= x² + x(-r - s) + rs

or, x² + bx + c = x² + x(-r - s) + rs

Comparing the related terms, we get:

b = (-r - s)

⇒ b + s = - r

or, s = -r - b

Now, given : r = Rational and the negative of a rational is also rational.

⇒ -r is also rational

Also, difference of two rational number is also rational.

⇒ -r - b is also rational

⇒ s is a RATIONAL NUMBER

Hence, the other solution of the given equation x² + bx + c = 0 is also rational number.

7 0

3 years ago

Is 1.65 greather than 16.5

Bas_tet [7]

Answer:

No

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Determine if they following is systems of equations? y = 3x + 2 y = 7x -10