1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VikaD [51]
3 years ago
5

The battery standby duration (in hours) of a new model of cell phone is known to be normally distributed. Ten pieces of such new

model of cell phone supplied from the manufacturer are randomly chosen and the actual standby durations are recorded as below:
48.2 47.8 45.6 47.2 49.3

51.2 44.2 45.4 49.2 43.6

(a) Calculate the unbiased estimates of population mean and standard deviation of battery standby duration (in hours) of the new cell phone.
Mathematics
1 answer:
kap26 [50]3 years ago
4 0

Answer:

\mu = 47.17

\sigma = 2.31

Step-by-step explanation:

Solving (a): The population mean

This is calculated as:

\mu = \frac{\sum x}{n}

So, we have:

\mu = \frac{48.2+ 47.8 +45.6 +47.2 +49.3+51.2 +44.2 +45.4 +49.2 +43.6}{10}

\mu = \frac{471.7}{10}

\mu = 47.17

Solving (b): The population standard deviation

This is calculated as:

\sigma = \sqrt{\frac{\sum (x - \mu)^2}{n}}

So, we have:

\sigma = \sqrt{\frac{(48.2-47.17)^2 + (47.8-47.17)^2 +.........+(43.6-47.17)^2}{10}}

\sigma = \sqrt{\frac{53.521}{10}}

\sigma = \sqrt{5.3521

\sigma = 2.31

You might be interested in
A number decreased by 16 is -3
aev [14]
Just add 16 to -3, then that will get your answer 13.
6 0
4 years ago
Read 2 more answers
Evaluate the expression.
Gemiola [76]

Answer:

98 is the answer of the expression

Step-by-step explanation:

AS it is a simple algebraic expression so these are solved by BDMAS rule which means that we have to solve the brackets first starting from the smaller bracket first which is inside a larger bracket then we will move to Division then multiplication then addition and then subtraction


so the following equation can be written as

= 2^{3}[\frac{1}{4}+4(36/12)]

First of all solving smallest bracket and division inside it

= 2^{3}[\frac{1}{4}+4(3)]

Multplying 4 inside

= 2^{3}[\frac{1}{4}+12]

Now solving the 2³

= 8[\frac{1}{4}+12]

Now solving the expression inside the bracket by taking LCM

= 8[\frac{1 + 4*12}{4}]

= 8[\frac{1 + 48}{4}]

= 8[\frac{49}{4}]

Now multiplying 8 with inside values

= [\frac{8*49}{4}]

AS 8 cuts out with 4 so

= 2 * 49

= 98

which is the answer of the expression



7 0
3 years ago
Soccer practice began at 2:30 PM and stopped at 3:00 PM because of the rain during this time through what fraction of a circle d
ICE Princess25 [194]
The hand turn 1 quarter of a circle (1/4). it turned 90 degrees

7 0
3 years ago
What is the slope of the function?
Zolol [24]
The slope of the function is 2!
3 0
3 years ago
15=3/5(6x + 20) solve for x
NISA [10]
This is the answer to the problem. Hope it helps
8 0
3 years ago
Other questions:
  • Amy loaned $5 to each of 20 people. She recorded each loan by writing $-5 in her bank book.
    10·1 answer
  • In triangle NQL, point S is the centroid, NS = (x + 10) feet, and SR = (x + 3) feet.
    9·2 answers
  • last year 120 students recived high honers at graduation. this year 144 students recived high honers. what was the percent incre
    10·2 answers
  • What is the domain of the function y= radical x?
    8·2 answers
  • Factor fully.<br> x2 + 5x + 6
    11·1 answer
  • Use one of the adding words, create a simple equation. (Number, key word, variable)
    9·1 answer
  • For the y= 2/3x , if the y coordinate is 14 what is the x coordinate? help asap
    5·2 answers
  • What do I do to get this answer? Could you provide me a step by step to understand where you get the numbers from? Thank you, wi
    9·1 answer
  • How do you say 1.0324 as a word
    13·1 answer
  • Jeremiah plans on building a 5 meter long garden walkway that is paved with square stones that measure meter on 56each side. The
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!