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Andrei [34K]
2 years ago
10

15=3/5(6x + 20) solve for x

Mathematics
1 answer:
NISA [10]2 years ago
8 0
This is the answer to the problem. Hope it helps
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A geometric sequence has an initial value of 9 and a common ratio of 5. What function could represent this situation?
leonid [27]

Answer:

The functions that represent this situation are A and C.

Step-by-step explanation:

A geometric sequence goes from one term to the next by always multiplying or dividing by the same value.

In geometric sequences, the ratio between consecutive terms is always the same. We call that ratio the common ratio.

This is the explicit formula for the geometric sequence whose first term is k and common ratio is r

6 0
3 years ago
Find the slope of the line passing through the points (8,-6) and (1, -2).​
Alik [6]

Step-by-step explanation:

The slope of the line is -4/7.

3 0
2 years ago
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Rose has 5 times as many stickers as John. They have 300 stickers in all. How many more stickers does Rose have than John? Show
kirill115 [55]

5x+x=300

6x=300

x=50

5(50)=250 (Rose)

x=50(John)

Rose has 250 stickers and John has 50, therefore Rose has 200 more stickers than John.

6 0
3 years ago
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How many ways can five people, a,b,c,d, and e, sit in a row at a movie theater if c must sit to the right of but not necessarily
hichkok12 [17]
A,b,c,d,e
a,b,d,c,e 
a,b,d,e,c
b,a,d,e,c
b,d,a,e,c
b,d,e,a,c

7 0
2 years ago
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A flyer is spread by people at a large conference. Within one hour, the first person gives a stack of flyers to six people. With
Mandarinka [93]

Answer:

In summation form \sum_{n = 1} ^{5} 6(6)^{n - 1}

Step-by-step explanation:

Within one hour, the first person gives a stack of flyers to six people and within the next hour, those six people give a stack of flyers to six new people.

So, in the first 5 hours, the summation of people that receive a stack of flyers not including the initial person will be given by

6 + (6 × 6) + (6 × 6 × 6) + (6 × 6 × 6 × 6) + (6 × 6 × 6 × 6 × 6).

So, in summation form \sum_{n = 1} ^{5} 6(6)^{n - 1}

Therefore, Sigma-Summation Underscript n = 1 Overscript 5 EndScripts 6 (6) Superscript n minus 1, gives the correct solution. (Answer)

3 0
3 years ago
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