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elixir [45]
3 years ago
13

Cost of 2 1/2 kg of potatoes is 30rs. what is the cost of 1 kg of potatoes

Mathematics
1 answer:
Art [367]3 years ago
6 0

Answer:

₹60

Just double the amount.....

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Is the number prime 5 and cmppsite or just one?
Serga [27]

If I understand what you are asking, the number 5 is prime. The definition for a prime number is a number that has no factors other than itself and one. The prime factorization of 5 is 5 * 1. Since 5's factors are only itself and 1, that means that it is prime. The definition of a composite number is a number that has at least one divisor other than one and itself. This means that a number cannot be both prime and composite.

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Read 2 more answers
If g (x) = 1/x then [g (x+h) - g (x)] /h
lys-0071 [83]

Answer:

\dfrac{-1}{x(x+h)}, h\ne 0

Step-by-step explanation:

If g(x) = \dfrac{1}{x}, then g(x+h) = \dfrac{1}{x+h}. It follows that

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

  = \dfrac{-1}{x(x+h)}, h\ne 0

5 0
3 years ago
Solve for u<br> 7=u/4-16
artcher [175]

Answer:

u=92

Step-by-step explanation:

Like and give 5 star rating

7 0
3 years ago
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