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2 years ago

Cost of 2 1/2 kg of potatoes is 30rs. what is the cost of 1 kg of potatoes

Mathematics

1 answer:

Art [367]2 years ago

6 0

Answer:

₹60

Just double the amount.....

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The Senior class held an election for class president. Pamela received three (3) votes for every two (2) votes Angela received.

likoan [24]

Answer:

Step-by-step explanation:

Divide 69 by 3

69 / 3 = 23

Take it times two.

23 x 2 = 46

Proportion

$\frac{3}{2} =\frac{69}{x}$

Cross multiply and solve for x.

6 0

3 years ago

You deposit $50 in your saving account. One week later, you withdraw $20. Write each amount as an integer.

Tju [1.3M]

Answer:

Depositing means that you added 50$ to your account. This means that you account increased by an amount of 50.

The integer describing this is +50.

Then, withdrawing means that you took money from the account. This means that your account decreased by an amount of 20.

This can be expressed as a -20 integer.

3 0

3 years ago

Need help on this questionnn

Alona [7]

The second option is the answer

5 0

2 years ago

Find the zeros of y = x2 – 6x – 4 by completing the square.

katrin [286]

Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

4 0

2 years ago

Please help me out with this please

ki77a [65]

Answer:

P = 9 is the max value

Step-by-step explanation:

Sketch

2x + 4y = 10

with x- intercept = (5, 0) and y- intercept (0, 2.5)

x + 9y = 12

with x- intercept = (12, 0) and y- intercept = (0, $\frac{4}{3}$ )

Solve

2x + 4y = 10 and x + 9y = 12 to find the point of intersection at (3, 1)

The region corresponding to the solution of the system of constraints

Has vertices at (0, $\frac{4}{3}$ ), (0, 0) , (5, 0) and (3, 1)

Now evaluate the objective function at each vertex.

(0, 0) can be excluded as it will not give a maximum

(5, 0) → P = 5 + 0 = 5

(0, $\frac{4}{3}$ ) → 0 + 8 = 8

(3, 1) → 3 + 6(1) = 3 + 6 = 9 ← maximum value

Thus the maximum value is 9 when x = 3 and y = 1

7 0

2 years ago