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3 years ago

Express the set using INTERVAL NOTATION -3<=x<10 Please help if you can

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

7 0

So x is from -3 to 10, including -3, but not including 10

so that would be the interval
[-3,10)
remember, the brackets [] are inclusive meaning ≤ and ≥
parenthasees () are not inclusive maning < and >

[-3,10)

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andre [41]

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3 years ago

Find the value of 7u+7 given that -3u-5=4

Serga [27]

Answer:

Step-by-step explanation:

-3u = 4+5

-3u = 9

u = -3

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2 years ago

C + 6 > 5c - 2<br>solved and proof

Elena L [17]

Hi there!

»»————-　★　————-««

I believe your answer is:

c < 2

»»————-　★　————-««

Here’s why:

⸻⸻⸻⸻

$c+6>5c - 2\\--------------\\\\\rightarrow5c - 2< c + 6 \leftarrow \text{Notice how the sides are switched.}\\\\\rightarrow 5c - c -2 < c - c + 6\\\\\rightarrow 4c -2 < 6\\\\\rightarrow 4c - 2 + 2 < 6 + 2\\\\\rightarrow 4c < 8\\\\\rightarrow \frac{4c$

⸻⸻⸻⸻

»»————-　★　————-««

Hope this helps you. I apologize if it’s incorrect.

4 0

3 years ago

Can I get some help please?

svetlana [45]

I believe that you already found the correct answer. But if it isn't I would just try 0.15.

4 0

3 years ago

Identify the relation that is also a function. A. {(-1, 1) (0, 0) (1, 1) (2, 4)} B. {(3, 4) (2, 3) (3, 6) (2, 0)} C. {(1, 0) (2,

madreJ [45]

Answer:

Step-by-step explanation:

We are given four sets of relations as

$A. {(-1, 1) (0, 0) (1, 1) (2, 4)} \\B. {(3, 4) (2, 3) (3, 6) (2, 0)} \\C. {(1, 0) (2, 3) (3, -2) (1, 6)} \\D. {(3, 2) (3, -2) (3, 6) (3, 8)}$

A function is a relation in which every element in the first set has a unique image in the second set.

Let us check this aspect to A.

This is a function

Now come to B. 3 has two images 4 and 6. so not a function

Next is C. in C 1 has two images 0 and 6. So not a function

For D, 3 has 4 images so not a function.

3 0

3 years ago