X + 2y = 3 solve for y
1 answer:
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we know that
If the only factors a polynomial are and itself, then that polynomial is prime.
so
If the polynomial has at least one root (one x-intercept) then the polynomial is not prime
Using a graph tool
<u>case 1) </u>
see the attached figure N 1
The polynomial has one root-------> the polynomial is not prime
<u>case 2) </u>
see the attached figure N 2
The polynomial has three roots-------> the polynomial is not prime
<u>case 3) </u>
see the attached figure N 3
The polynomial has zero roots-------> the polynomial is prime
<u>case 4)</u>
see the attached figure N 4
The polynomial has two roots-------> the polynomial is not prime
therefore
<u>the answer is</u>
------> is prime
