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2 years ago

How to solve the Quadratic formul

Mathematics

1 answer:

Marat540 [252]2 years ago

7 0

Answer:

The answer is x=-6, x=8

Step-by-step explanation:

I recommend using the quadratic formula to solve this problem.

x^2=a

-2x=b

-48=c

Plug it into the quadratic formula.

New equation: $\frac{2+-\sqrt{(-2)^2-4(1)(-48)}}{2(1)}$

Simplify

Equation: $\frac{2+-\sqrt{4+192}}{2}$

Add 4 and 192.

Equation: $\frac{2+-\sqrt{196}}{2}$

Do the square root of 196.

Equation: $\frac{2+-14}{2}$

Make into two different equations.

Equation 1: $\frac{2+14}{2}$

Equation 2: $\frac{2-14}{2}$

Solve the two equations and you will get -6 and 8. Hope this helps!

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What is larger 2.044 or 2.04

Rudik [331]

2.044 by just 0.004 units

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2 years ago

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Nikolai has a jar filled with 120 marbles. he has 72 red marbles, 17 blue marbles, 13 green marbles, and 18 purple marbles. what

asambeis [7]

To find the probability of both of these occurring, you will multiply the probability of choosing a blue marble by the probability of choosing a purple marble (with no replacement after the first one).

Probability of choosing a blue marble: 17/120
Probability of choosing a purple marble: 18/119

17/120 x 18/119 = 3/140

You will have a 3/140 chance of both of these occurring.

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2 years ago

There are 527 pencils,646 erasers,748 sharpeners . these are to be put in separate packets containing the same no. of items. fin

Ksju [112]

$To \; find \; the \; maximum \; number \; of \; items \; possible \; in each \; packet,\\we \; need \; to \; find \; the \; Greatest \; Common \; Factor\\ \; of \; 527 \; Pencils, \; 646 \; erasers \; and \; 748 \; sharpeners.\\\\We \; need \; to \; list \; the \; Factors \; of \; each \; number \; as \; given \; below\\ \; and \; identify \; the \; greatest \; common \; factor.$

$The \; factors \; of \; 527 \; are:\\1, \; 17, \; 31, \; 527\\\\The \; factors \; of \; 646 \; are:\\1, \; 2, \; 17, \; 19, \; 34, \; 38, \; 323, \; 646\\\\The \; factors \; of \; 748 \; are:\\1, \; 2, \; 4, \; 11, \; 17, \; 22, \; 34, \; 44, \; 68, \; 187, \; 374, \; 748\\\\Then \; the \; greatest \; common \; factor \; is \; 17.$

$Conclusion: \\There \; will \; 31 \; Pencils, \; 38 \; Erasers,\\ \; and \; 44 \; Sharpeners \; in \; each \; of \; SEVENTEEN \; packet.$

4 0

2 years ago

Can someone help me? And possibley tell me how to solve this as well? I'm totally clueless haha

Bumek [7]

Answer:

? = 3

Step-by-step explanation:

To find the value of ?, substitute one of the ordered pairs from the table [except (0, 0)] into the given formula and solve for ?.

Given formula:

$\sf y=\boxed{?} \:x$

Substitute x = 1 and y = 3 into the formula:

$\sf 3=\boxed{?} \:1$

To isolate ? divide both sides by 1:

$\implies \sf \dfrac{3}{1}=\dfrac{\boxed{?} \:1}{1}$

$\implies \sf 3=\boxed{?}$

Therefore, ? = 3:

$\implies \sf y=3x$

Check by inputting another value of x from the table into the found formula and comparing the calculated y-value:

$\sf x=-2 \implies y=3(-2)=-6 \quad \boxed{\sf correct}$

$\sf x=3 \implies y=3(3)=9 \quad \boxed{\sf correct}$

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1 year ago

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What are the chances of flipping a coin 12 times and it landing on heads 11 times?

lubasha [3.4K]

12 flips, 11 heads, 1 tails
Let's say there's a 50-50 chance of landing heads.
There are 12 flips and 12 specific outcomes.
The probability is 2^(-12) = 1/4096 = 0.0244%

If the last flip doesn't matter, then the probability would be 2^(-11) = 1/2048 = 0.0488%.

Have an awesome day! :)

From your friendly Helper-in-Training, collinjun0827

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2 years ago

How to solve the Quadratic formul​

How to solve the Quadratic formul