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3 years ago

How would I solve this?

Mathematics

1 answer:

denis23 [38]3 years ago

4 0

Subsitute 7 for x

√(2k²+17)-7=0
add 7 to both sides
√(2k²+17)=7
squaer both sides
2k²+17=49
minus 17 both sides
2k²=32
divide both sides by 2
k²=16
square both sides
k=+/-4

we are given that k>0 so k=4

answer is C

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Answer:

In the year 2010

Step-by-step explanation:

we have

$A=200e^{0.033t}$

where

A is the population in thousands

t is the number of years since 1998

For A=297 thousands

substitute and solve for t

$297=200e^{0.033t}$

simplify

$1.485=e^{0.033t}$

Apply ln both sides

$ln(1.485)=ln[e^{0.033t}]$

$ln(1.485)=(0.033t)ln(e)$

Remember that

$ln(e)=1$

$ln(1.485)=(0.033t)$

$t=\frac{ln(1.485)}{0.033}$

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3 years ago

Find the balance in the account after the given period.

Lapatulllka [165]

Answer:

balance after 4 years = $4502

Step-by-step explanation:

Formula to get the final amount when compounded annually is,

Final amount = $\text{Principal amount}\times (1+\frac{r}{n})^{nt}$

Here, r = rate of interest

n = number of compounding per year

t = Duration of investment

From the given question,

Final amount = $4000(1+\frac{0.03}{1})^{(1\times 4)}$

= $4000(1.03)^4$

= 4502.0352

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Therefore, balance after 4 years = $4502

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olga55 [171]

Answer:

Step-by-step explanation:

30-22=8

22-14=8

14-6=8

then

→ the common difference r = 8

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THerefore, (accoriding to the standard explicit formula)

the 64th term = term 1 + (64 - 1)×r

= 6 + 63×8

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