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Masteriza [31]
3 years ago
13

HELPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics
2 answers:
murzikaleks [220]3 years ago
8 0
The angles below AB will add to 180°.
.. x +2x +x +3x = 180°
.. 7x = 180°
.. x = 180°/7 ≈ 25.71°

Vertical angles AOC and BOD are equal, so
.. 2y = 3x
.. y = (3/2)*x = (3/2)*25.71° = 38.6° . . . . . . . . corresponding to selection D.

___
There is an "x" missing next to segment OC. "2" should be "2x".
Makovka662 [10]3 years ago
6 0
Notice that 2y and 3x are vertical angles, which means they are equal.
2y=3x

the four angles below the line AB make a sum of 180
 3x+x+2x+x=180
7x=180
x=180/7

2y=3x=3*180/7=540/7
y=270/7≈38.6
d is the answer.

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Answer is 47.25

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A mail courier charges a base fee of $6.95 plus $7.60 per package being delivered. If x represents the number of packages delive
castortr0y [4]
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Hope this helps.
5 0
3 years ago
Find the value of x at which the function has a possible relative maximum or minimum point.​ (Recall that e Superscript x is pos
shutvik [7]

Answer:

x= -11/4 is a maximum.

Step-by-step explanation:

Remember that a function has its critical points where the derivative equal zero. Therefore we need to compute the derivative of this function and find the points where the derivative is zero. Using the chain rule and the product rule we get that

f'(x)=  -e^{-4x}(11+4x)

And then we get that   if   11+4x = 0   then   x = -11/4 . So it has a critical point at   x = -11/4.

Now, if the second derivative evaluated at that point is less than 0 then the point is a maximum and if is greater than zero the point is a minimum.

Since

f''(x) = 8e^{-4x} (5+2x)\\f''(-11/4) = -239496.56

x= -11/4 is a maximum.

6 0
3 years ago
A ball is thrown straight up from a height of 3 ft with a speed of 32 ft/s. Its height above the ground after x seconds is given
IceJOKER [234]

Answer:

19ft

Step-by-step explanation:

Given the height of a ball above the ground after x seconds given by the quadratic function y = -16x2 + 32x + 3, we can find the maximum height reached by the ball since we are not told what to look for.

The velocity of the ball is zero at maximum height and it is expressed as:

V(x) = dy/dx

V(x) = -32x+32

Since v(x) = 0

0 = -32x+32

32x = 32

x = 32/32

x = 1s

Get the height y

Recall that y = -16x² + 32x + 3.

Substitute x = 1

y = -16(1)²+32(1)+3

y = -16+32+3

y = -16+35

y = 19ft

Hence the maximum height reached by the ball is 19ft

7 0
3 years ago
I need to know the answer to this question above please it’s for math homework!!!
Nadusha1986 [10]
The answer to the problem is 5
3 0
3 years ago
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