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Pavlova-9 [17]
3 years ago
5

Find the length of the missing side (nearest tenth). 19 in 25 in

Mathematics
1 answer:
Softa [21]3 years ago
7 0
Not sure if I’m right but in the picture I have the answer and the work along with it

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Find the value of x 2-x7=25
o-na [289]

Answer: 3.285714286

Step-by-step explanation: subtract 2 from both sides then divide by 7

4 0
3 years ago
Simplifying expressions with exponents
REY [17]
When dividing two terms with the same base, subtract the exponent in the denominator from the exponent in the numerator: Power of a Power: To raise a power to a power, multiply theexponents. 
8 0
2 years ago
Read 2 more answers
PLEASE SOLVE FOR QUESTION 13!!!!!
Reptile [31]
X + x + x + 20 + 10 = 180
(combine like terms)
3x + 30 = 180
3x=180-30
3x=150
x=150/3
x=50
8 0
3 years ago
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In Inglis County me were 2,277 student athletes competing in spring sports in 2014. Thai was of the number which was of the numb
Anna35 [415]
2014⇒2277 athletes

2013⇒2070 athletes.
x=number of athletes in 2013
110% of x=2277
(110/100x=2277
x=(2277*100)/110=2070

2012⇒2300 athletes. 
x=number of athletes in 2012
90% of x=2070
(90/100)x=2070
x=(2070*100)/90=2300

Answer: 2300 athletes were signed up for a spring sport in 2012. 
7 0
3 years ago
4 days I have 140 copies of a book, 9 days I only have 50 left. Write an equation where c(t)=my+b where c is number of copies st
alexandr402 [8]

Answer:

c(t)=-18t+212.

Step-by-step explanation:

We have been given that 4 days I have 140 copies of a book, 9 days I only have 50 left. We are asked to write an equation c(t)=my+b, where c is number of copies still on hand and t days being available.

We have two points on line (4,140) and (9,50). Now, we will use these points to find slope as:

m=\frac{140-50}{4-9}

m=\frac{90}{-5}

m=-18

Now, we will use point-slope form of equation y-y_1=m(x-x_1) and substitute m=-18 and coordinates of point (9,50) as:

y-50=-18(x-9)

y-50=-18x+162

y-50+50=-18x+162+50

y=-18x+212

Therefore, our required equation would be c(t)=-18t+212.

5 0
3 years ago
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