20 units Humulin R insulin in 100 mL of normal saline (NS) to infuse for 20 hours. (Round to the nearest tenth if applicable) a.
1 answer:
Answer:
a) 1 unit per hour will be infused.
b) 5mL per hour will be infused.
Step-by-step explanation:
Each question can be solved as a rule of three with direct measures, that means we have a cross multiplication.
a. How many units per hour will be infused?
20 units are going to be infused in 20 hours. How many units are going to be infused each hour?
1 hour - x units
20 hours - 20 units
1 unit per hour will be infused.
b. How many milliliters per hour will be infused?
100mL are going to be infused in 20 hours. How many mL are going to be infused each hour?
1 hour - x mL
20 hours - 100 mL
5mL per hour will be infused.
You might be interested in
<span>The graph is attached.
Explanation:
We can use the x- and y-intercepts to graph. The x-intercept of the first equation is 8, and the y-intercept is 8. The x-intercept of the second equation is -2, and the y-intercept is 2.
<span>
x-intercepts are where the data crosses the x-axis. At every one of these points, the y-coordinate will be 0; therefore we can substitute 0 for y and solve to get the value of the x-intercept.
For the first equation, we would have
8x+8(0)=64
8x=64.
Divide both sides by 8:
8x/8 = 64/8
x=8.
For the second equation,
2x-2(0)=-4
2x=-4.
Divide both sides by 2:
2x/2 = -4/2
x=-2.
y-intercepts are where the data crosses the y-axis. At every one of these points, the x-coordinate will be 0; therefore we can substitute 0 for x and solve to get the value of the y-intercept.
For the first equation,
8(0)+8y=64
8y=64.
Divide both sides by 8:
8y/8 = 64/8
y=8.
For the second equation,
2(0)-2y=-4
-2y=-4.
Divide both sides by -2:
-2y/-2 = -4/-2
y=2.
Plot these points for both equations and connect them to draw the line.</span></span>
Explanation:
We can use the x- and y-intercepts to graph. The x-intercept of the first equation is 8, and the y-intercept is 8. The x-intercept of the second equation is -2, and the y-intercept is 2.
<span>
x-intercepts are where the data crosses the x-axis. At every one of these points, the y-coordinate will be 0; therefore we can substitute 0 for y and solve to get the value of the x-intercept.
For the first equation, we would have
8x+8(0)=64
8x=64.
Divide both sides by 8:
8x/8 = 64/8
x=8.
For the second equation,
2x-2(0)=-4
2x=-4.
Divide both sides by 2:
2x/2 = -4/2
x=-2.
y-intercepts are where the data crosses the y-axis. At every one of these points, the x-coordinate will be 0; therefore we can substitute 0 for x and solve to get the value of the y-intercept.
For the first equation,
8(0)+8y=64
8y=64.
Divide both sides by 8:
8y/8 = 64/8
y=8.
For the second equation,
2(0)-2y=-4
-2y=-4.
Divide both sides by -2:
-2y/-2 = -4/-2
y=2.
Plot these points for both equations and connect them to draw the line.</span></span>