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erastovalidia [21]
3 years ago
7

Solve for x: ✓72 +95 – 1 = 8 What would X be?

Mathematics
2 answers:
Flauer [41]3 years ago
7 0
2 mil. That would finish the process
lesya [120]3 years ago
3 0
2 MILLIONNNNNNNNNNNNNNNNNN
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Is 2 (x-y) and 2x-2y equivalent
MArishka [77]

Answer:

yes

Step-by-step explanation:

2(x-y) you distribute the 2 to whats inside the parenthesis

2x-2y

4 0
3 years ago
The perimeter of a rectangular garden is 43.8 feet. Its length is 12.4 feet. What is its width?
Veseljchak [2.6K]

Answer:

9.5 ft

Step-by-step explanation:

12.4 times 2 is 24.8 feet (this is the two lengths combined)

since the garden is 43.8 feet, subtract.  43.8 - 24.8 = 19

lastly, 19 divided by 2 is 9.5.

8 0
3 years ago
Read 2 more answers
Help please........​
german
21x-9+63=180
21x+54=180
21x=126
x=6
4 0
2 years ago
Answer It, Thanks. -3(-100)
Kaylis [27]

Answer: 300

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
In a free-fall experiment, an object is dropped from a height of h = 400 feet. A camera on the ground 500 ft from the point of i
PilotLPTM [1.2K]
Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s

the only force acting on the object, is gravity, using feet will then be -32ft/s²,


was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues

so, we'll do the integral to get v(t) then

\bf \displaystyle \int -32\cdot dt\implies -32t+C
\\\\\\
\textit{object moves from \underline{rest}, so velocity is 0 at 0secs}
\\\\\\
-32(0)+C=0\implies C=0\implies \boxed{v(t)=-32t}
\\\\\\
\textit{now to get the positional s(t)}
\\\\\\
\displaystyle \int -32t\cdot dt\implies -16t^2+C
\\\\\\
\textit{the initial \underline{position} was 400ft away at 0secs}
\\\\\\
-16(0)^2+C=400\implies C=400\implies \boxed{s(t)=-16t^2+400}

when will it reach the ground level? let's set s(t) = 0

\bf s(t)=-16t^2+400\implies 0=-16t^2+400\implies \cfrac{-400}{-16}=t^2
\\\\\\
25=t^2\implies \boxed{5=t}


part B)  check the picture below

5 0
2 years ago
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