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Vitek1552 [10]
3 years ago
15

Add 5 to me.Then divide by 7.If you add 12 and the subtract 7,you get 10

Mathematics
1 answer:
qaws [65]3 years ago
6 0

Answer: 30

Step-by-step explanation:

Let the number be y

Add 5 to me

Y+5............equ1

Divide by 7

Y+5/7

Add 12

Y+5/7+12

Subtract 7

(Y+5)/7+(12-7)=10

12-7=5

Substitute

(Y+5)/7+5=10

Find the lowest common multiple

((Y+5)+7(5))/7=10

(Y+5)+35)/7=10

Cross multiply

Y+5+35=70

Y+40=70

Y=70-40

Y=30

The unknown number is 30

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Answer:

84%

Step-by-step explanation:

The empirical rule states that 68% values are within 1 standard deviation of mean, i.e,

70

±

15

or from 55 to 85. Since normal distribution is symmetric, we must have (32%) outside this range, and 32/2=16% on the right if this range. Hence below 85 we have (100-16) % = 84%

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3 years ago
Formula to find the missing number Faces:15 vertices:15 edges:?
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Answer:

Step-by-step explanation:

Euler's formula is

V - E + F = 2

Givens

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E = 15

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I'm not sure this makes sense, but it is what the formula gives you.

7 0
3 years ago
PLEASE HELP!!
ElenaW [278]

Answer:

-1 and -3

(n+7)(n-8)

Step-by-step explanation:

1. Find the Zeros

f(x)=x^{2} +4x+3

f(x)=\left(x+1\right)\left(x+3\right)

x+1=0\\x=-1\\x+3=0\\x=-3

2. Factoring Trinomials

f(x)=n^{2} -n-56

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4 0
3 years ago
Marco and his two younger sisters would like to purchase a silver charm bracelet for their mother’s birthday. they went to the m
ioda

Function would be f(x) = 5x+85

here, x= 15

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8 0
3 years ago
How many oz of walnuts which cost $6/oz must be added to 2 oz of peanuts which cost $12/oz to make mixed nuts which cost $8/oz
Burka [1]

Answer:  4 oz

<u>Step-by-step explanation:</u>

Create a table.  Multiply across and add down (the middle column cannot be added).  The Mixture line creates the equation that must be solved.

Let x represent the unknown quantity of walnuts.

\begin{array}{c|c|c||c}&\underline{Quantity}&\underline{Cost}&\underline{Qty \times Cost}\\Walnuts&x&6&6x\\\underline{Peanuts}&\underline{\qquad 2\qquad}&\underline{\qquad 12\qquad}&\underline{\qquad 24\qquad }\\Mixture&x+2&8&6x+24\end{array}

.\qquad \qquad \qquad \qquad (x+2)(8) = 6x+24\\.\qquad \qquad \qquad \qquad 8x + 16 = 6x + 24\longrightarrow \text{distributed}\\.\qquad \qquad \qquad \qquad2x+16=24\qquad \longrightarrow \text{subtracted 6x}\\.\qquad \qquad \qquad \qquad 2x=8\qquad \qquad \ \longrightarrow \text{subtracted 16}\\.\qquad \qquad \qquad \qquad x=4\qquad \qquad \quad \longrightarrow \text{divided by 2}

4 0
3 years ago
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