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2 years ago

Help me with this FOIL method.

Mathematics

1 answer:

kumpel [21]2 years ago

3 0

So u have got a quadratic. Two numbers which times together to give -35 and + to give 2 are -5 and 7 so in the bracket it would be (p-5)(p+7)

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Someone please help me I’ll give out brainliest please dont answer if you don’t know

Ede4ka [16]

Answer:

x = 3

Step-by-step explanation:

9x - 5 = 22

Add 5 to both sides

9x = 27

Divide both sides by 9

x = 3

4 0

2 years ago

Give the equation of the line perpendicular to the line through (3, 2) and (-2, 4) that

AVprozaik [17]

Answer:

Step-by-step explanatio

5 0

3 years ago

The measure of two supplementary angles are (3x - 10°) and (6x+100). What is the measure of the smaller angle?

kolezko [41]

Answer: 20 degrees

Step-by-step explanation:

You add both angle for them to equal 180
You solve for x
3x-10=20; 6x+100=120

3 0

3 years ago

Over which interval(s) is the function decreasing? Please help me I will thank you and give you five stars ⭐️

Elena-2011 [213]

There’s no picture so I can’t help you I’m sorry :(

4 0

3 years ago

The logarithm of a number to the base V2 is k. What is its logarithm to the base 2v2 ?

kakasveta [241]

Answer:

$log_{2\sqrt 2} X = \frac{1}{3}k$

Step-by-step explanation:

Given

Let the number be X

From the first statement, we have:

$log_{\sqrt 2} X = k$

Required

Find $log_{2\sqrt 2} X$

$log_{\sqrt 2} X = k$

using the following law of logarithm

$log_ab = n, b=a^n$

So:

$log_{\sqrt 2} X = k$

$X = \sqrt{2}^k$

Substitute: $X = \sqrt{2}^k$ in $log_{2\sqrt 2} X$

$log_{2\sqrt 2} X = log_{2\sqrt 2} ( \sqrt{2}^k)$

$log_{2\sqrt 2} X = klog_{2\sqrt 2} \sqrt{2}$

Apply the following law:

$log_ab = \frac{log\ b}{log\ a}$

$log_{2\sqrt 2} X = k\frac{log\ \sqrt 2}{log\ {2\sqrt 2}}$

Express the square roots as power

$log_{2\sqrt 2} X = k\frac{log\ 2^\frac{1}{2}}{log\ {2 * 2^\frac{1}{2}}}$

$log_{2\sqrt 2} X = k\frac{log\ 2^\frac{1}{2}}{log\ {2^\frac{3}{2}}}$

using the following law of logarithm

$log_ab = n, b=a^n$

$log_{2\sqrt 2} X = k\frac{\frac{1}{2}log\ 2}{\frac{3}{2}log\ 2}}$

$log_{2\sqrt 2} X = k\frac{\frac{1}{2}}{\frac{3}{2}}}$

Rewrite as:

$log_{2\sqrt 2} X = k * \frac{1}{2} \div\frac{3}{2}$

$log_{2\sqrt 2} X = k * \frac{1}{2} *\frac{2}{3}$

$log_{2\sqrt 2} X = k * \frac{1}{1} *\frac{1}{3}$

$log_{2\sqrt 2} X = \frac{1}{3}k$

4 0

2 years ago