Area of Rectangle C is 2, if scale factor of 1/5 is applied to length and width of Rectangle B.
Step-by-step explanation:
Length of Rectangle B= 5
Width of Rectangle B = 10
Scale factor: 1/5
Area of Rectangle C=?
Length of Rectangle C= 
Width of Rectangle C = 
So, Area after applying Scale factor for Rectangle C will be:
So, Area of Rectangle C is 2 if scale factor of 1/5 is applied to length and width of Rectangle B.
Keywords: Area of Rectangle
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I guess the chef is making the mixture for the sheriff... Let <em>x</em> be the amount of dressing with 5% vinegar that is required, and <em>y</em> the amount of 15% vinegar dressing (both amounts in mL).
The sheriff wants 390 mL of the mixed dressing, so that
<em>x</em> + <em>y</em> = 390
<em>x</em> mL of the 5% dressing contains 0.05<em>x</em> mL of vinegar, while <em>y</em> mL of the 15% dressing contains 0.15<em>y</em> mL of vinegar. The resulting mixture should have a concentration of 9% vinegar, so that it contains 0.09 (390 mL) = 35.1 mL of vinegar. This means
0.05<em>x</em> + 0.15<em>y</em> = 35.1
Solve for <em>x</em> and <em>y</em> :
<em>y</em> = 390 - <em>x</em>
0.05<em>x</em> + 0.15 (390 - <em>x</em>) = 35.1
0.05<em>x</em> + 58.5 - 0.15<em>x</em> = 35.1
23.4 = 0.10<em>x</em>
<em>x</em> = 234
<em>y</em> = 156
Answer:
log2(M)+log3(N)
simplifies to:
simplified step by step
Step-by-step explanation:
0.30103m+0.477121n.
the answer is
0.39103m+0.477121n
