The correct statement about the earthquake in the state is option c. State A had approximately 3,362 more earthquakes than State B.
<h3>How to solve for the earthquake in the state A</h3>
we have x/y = 0.00299
y = 163696
To solve for x we have
163696 * 0.00299
= 4895 earthquakes
<h3>Next we have to solve for earth quakes in state B</h3>
x = 0.1402 x 10931
= 1533
Next we have to find the difference
4895 - 1533 = 3362 earthquakes.
We have to conclude that state A has 3362 earthquakes more than B. Hence the answer is c.
<h3 />
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Complete question
The seismic activity density of a region is the ratio of the number of earthquakes during a given time span to the land area affected. The table shows the land area and seismic activity density.
Which statement about the number of earthquakes the states had for the given time span is true?
State A had approximately 1,533 more earthquakes than State B.
State B had approximately 1,533 more earthquakes than State A.
State A had approximately 3,362 more earthquakes than State B.
State B had approximately 3,362 more earthquakes than State A.
<span>There are 4 long rows and 5 short rows in the theater. x represents the number of chairs in each long row and y represents the number of chairs in each short row.
So, total number of chairs in 4 long rows= 4x
Total number of chairs in 5 short rows = 5y
Total number of chairs in the theater on a normal day = 4x + 5y
When 2 chairs are added to each long row, the number of chairs will change to (x+2).
So, total number of chairs in 4 long rows will be = 4(x+2)
When 3 chairs are added to each short row, the number of chairs will change to (y+3)
So, total number of chairs in 5 short rows will be = 5(y+3)
Thus, total number of chairs in the theater in rush day = 4(x+2) + 5(y+3)
= 4x + 8 + 5y + 15
= 4x + 5y + 23
Thus we can say the number of chairs increase by 23 as compared to a normal day.
</span>
The arc length, radius and the included angle are related as
where 
is in radians.
The radius 
is given by
Correct choice is (B).
Answer:
1. Objective function is a maximum at (16,0), Z = 4x+4y = 4(16) + 4(0) = 64
2. Objective function is at a maximum at (5,3), Z=3x+2y=3(5)+2(3)=21
Step-by-step explanation:
1. Maximize: P = 4x +4y
Subject to: 2x + y ≤ 20
x + 2y ≤ 16
x, y ≥ 0
Plot the constraints and the objective function Z, or P=4x+4y)
Push the objective function to the limit permitted by the feasible region to find the maximum.
Answer: Objective function is a maximum at (16,0),
Z = 4x+4y = 4(16) + 4(0) = 64
2. Maximize P = 3x + 2y
Subject to x + y ≤ 8
2x + y ≤ 13
x ≥ 0, y ≥ 0
Plot the constraints and the objective function Z, or P=3x+2y.
Push the objective function to the limit in the increase + direction permitted by the feasible region to find the maximum intersection.
Answer: Objective function is at a maximum at (5,3),
Z = 3x+2y = 3(5)+2(3) = 21
