The sides of the triangle are given as 1, x, and x².
The principle of triangle inequality requires that the sum of the lengths of any two sides should be equal to, or greater than the third side.
Consider 3 cases
Case (a): x < 1,
Then in decreasing size, the lengths are 1, x, and x².
We require that x² + x ≥ 1
Solve x² + x - 1 =
x = 0.5[-1 +/- √(1+4)] = 0.618 or -1.618.
Reject the negative length.
Therefore, the lengths are 0.382, 0.618 and 1.
Case (b): x = 1
This creates an equilateral triangle with equal sides
The sides are 1, 1 and 1.
Case (c): x>1
In increasing order, the lengths are 1, x, and x².
We require that x + 1 ≥ x²
Solve x² - x - 1 = 0
x = 0.5[1 +/- √(1+4)] = 1.6118 or -0.618
Reject the negative answr.
The lengths are 1, 1.618 and 2.618.
Answer:
The possible lengths of the sides are
(a) 0.382, 0.618 and 1
(b) 1, 1 and 1.
(c) 2.618, 1.618 and 1.
-.1666667
You can use khan academy or Socratic if you still not sure.
Answer: 42°
<u>Step-by-step explanation:</u>
HJ is an angle bisector of ∠IHK so
∠IHJ ≅ ∠KHJ ⇒ m∠IHJ = m∠KHJ
3a + 6 = 5a - 18
6 = 2a - 18
24 = 2a
12 = a
∠IHJ = 3a + 6
= 3(12) + 6
= 36 + 6
= 42
Answer:
Step-by-step explanation:
Sine is opposite divided by the hypotenuse.
sin(30) = 9/y
1/2 = 9/y
y = 18
Cosine is adjacent divided by the hypotenuse
cos(30) = x/18
