Answer:
3y -- 6
Step-by-step explanation:
if the largest number is y, then the other two integers would be (y -- 2) and (y -- 4).
Therefore the sum of the integers would be
y + (y -- 2) + (y -- 4) = 3y -- 6.
2
m^2 + 5m - 4
Let m = -6
( -6) ^2 + 5(-6) -4
Exponents first
36 + 5(-6) -4
Then multiply
36 -30 -4
Then subtract
6 -4
