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ratelena [41]
3 years ago
10

Estimate how many times larger 4 x 10^15 is than 8 x 10^9 in the form of a single digit times an integer power of 10.

Mathematics
1 answer:
Nuetrik [128]3 years ago
5 0

Problem A

When you use the term larger, you mean that (if the power is positive) the bigger number is in the numerator. 4*10^15 > 8 * 10^9 So 8 * 10^9  is in the denominator

Solution

\dfrac{4*10^{15}}{8*10^9} =0.5*10^6 =0.5*10^1*10^5=5*10^5

Note:The tricky part is recognizing what to do with the 0.5 * 10^6. You can always break apart a power into it's parts. Since 6 = 5 + 1, the power can be broken down into 10^1*10^5. The 10^1 is used to get the 0.5 to a number that is a single digit.

Problem 2

I'm just going to give you the answer to this. Please use Problem A as a guide.

\dfrac{2*10^-5}{4*10^-12} = \dfrac{0.5*10^{-5}*10^{12}}{1} = 5*10^6

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masya89 [10]

We have to determine the complete factored form of the given polynomial

f(x)=6x^3-13x^2-4x+15.

Let x= -1 in the given polynomial.

So, f(-1)= 6(-1)^3-13(-1)^2-4(-1)+15 = -6-13+4+15 = 0

So, by factor theorem

(x+1) is a factor of the given polynomial.

So, dividing the given polynomial by (x+1), we get quotient as 6x^2-19x+15.

So, 6x^3-13x^2-4x+15 = (x+1)6x^2-19x+15.

= (x+1)(6x^2-10x-9x+15)

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Option D is the correct answer.

5 0
3 years ago
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ꞮɴᴇQᴜᴀʟɪᴛʏ Qᴜᴇꜱᴛɪᴏɴ, ᴘʟᴇᴀꜱᴇ ʜᴇʟᴘ ᴍᴇ ᴏᴜᴛ
zaharov [31]
B I have done this before
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3 years ago
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Question 3. Solve each equation given<br>below.<br>5 x - 4=31​
harkovskaia [24]

Answer:

x = 7

Step-by-step explanation:

5x-4 = 31

5x = 31+4

5x = 35

x = 7

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2 years ago
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