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ratelena [41]
3 years ago
10

Estimate how many times larger 4 x 10^15 is than 8 x 10^9 in the form of a single digit times an integer power of 10.

Mathematics
1 answer:
Nuetrik [128]3 years ago
5 0

Problem A

When you use the term larger, you mean that (if the power is positive) the bigger number is in the numerator. 4*10^15 > 8 * 10^9 So 8 * 10^9  is in the denominator

Solution

\dfrac{4*10^{15}}{8*10^9} =0.5*10^6 =0.5*10^1*10^5=5*10^5

Note:The tricky part is recognizing what to do with the 0.5 * 10^6. You can always break apart a power into it's parts. Since 6 = 5 + 1, the power can be broken down into 10^1*10^5. The 10^1 is used to get the 0.5 to a number that is a single digit.

Problem 2

I'm just going to give you the answer to this. Please use Problem A as a guide.

\dfrac{2*10^-5}{4*10^-12} = \dfrac{0.5*10^{-5}*10^{12}}{1} = 5*10^6

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In the problem, 2x4 - 3x3 - 6x2 + 11x +8 divided by (x - 2), what is the remainder?
Jet001 [13]

remainder = 14

2x^{4} - 3x^{3} - 6x² + 11x + 8

= 2x³ + x² - 4x + 3 + \frac{14}{x - 2}


8 0
3 years ago
A taxi travels 25 km east of airport. Then it travels from that point to a point that is 40 km west of the airport. Finally the
Marizza181 [45]
The answer is:  " 95 km " .
__________________________________________________
Explanation:
__________________________________________________

                                   ("airport")
                                           •     {Step 1):       " 25 km east "               •<span>  
                                           </span>│===============================>  <span>│

                           </span>•  {Step 2):       " 40 km west ["of that point"] " ;        •                                             │<==========================================│<span>  
             
                          </span>•  {Step 3:  [back to airport] = " (40 km − 25 km) " ;

                                            • ("airport").
                         │=======>│
<span> _________________________________________________
                          
<u> Note</u>:  To find "total distance traveled:

" 40 km +</span> (40 km) + (40 km <span>− 25 km) " ; 

= </span>" 40 km + (40 km) + (15 km) " ;

= " 40 km + 40 km + (15 km) " ;

= 80 km + 15 km  ;   

=  95 km .
____________________________________________________
<span>
The answer is:  " 95 km <span>" .
</span>____________________________________________________

</span>
4 0
3 years ago
Find a set of parametric equations for y= 5x + 11, given the parameter t= 2 – x
Sati [7]

Answer:

x = 2-t and y = -5\cdot t +21

Step-by-step explanation:

Given that y = 5\cdot x + 11 and t = 2-x, the parametric equations are obtained by algebraic means:

1) t = 2-x Given

2) y = 5\cdot x +11 Given

3) y = 5\cdot (x\cdot 1)+11 Associative and modulative properties

4) y = 5\cdot \left[(-1)^{-1} \cdot (-1)\right]\cdot x +11 Existence of multiplicative inverse/Commutative property

5) y = [5\cdot (-1)^{-1}]\cdot [(-1)\cdot x]+11 Associative property

6) y = -5\cdot (-x)+11  \frac{a}{-b} = -\frac{a}{b} / (-1)\cdot a = -a

7) y = -5\cdot (-x+0)+11 Modulative property

8) y = -5\cdot [-x + 2 + (-2)]+11 Existence of additive inverse

9) y = -5 \cdot [(2-x)+(-2)]+11 Associative and commutative properties

10) y = (-5)\cdot (2-x) + (-5)\cdot (-2) +11 Distributive property

11) y = (-5)\cdot (2-x) +21 (-a)\cdot (-b) = a\cdot b

12) y = (-5)\cdot t +21 By 1)

13) y = -5\cdot t +21 (-a)\cdot b = -a \cdot b/Result

14) t+x = (2-x)+x Compatibility with addition

15) t +(-t) +x = (2-x)+x +(-t) Compatibility with addition

16) [t+(-t)]+x= 2 + [x+(-x)]+(-t) Associative property

17) 0+x = (2 + 0) +(-t) Associative property

18) x = 2-t Associative and commutative properties/Definition of subtraction/Result

In consequence, the right answer is x = 2-t and y = -5\cdot t +21.

5 0
3 years ago
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nikitadnepr [17]

Answer:

Step-by-step explanation:

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Sorry, don't want to give away all the answers!

Hope this helps!!!

7 0
3 years ago
One hundred samples of five data points were randomly selected from each of four populations. The medians of each population's s
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B my sister did this on a p e x
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