Answer:
Ionization energy of is 54.4 eV.
Explanation:
where,
= energy of orbit
n = number of orbit
Z = atomic number
Energy of n = 1 in an hydrogen like atom:
Energy of n = ∞ in an hydrogen like atom:
Ionization energy of =
Answer:
dehydration
Explanation:
Anabolic reactions in cells frequently employ dehydration synthesis as a. mechanism for building complex macromolecules.
5.7% KCl is 94.3 % water.
Therefore, for 1000 g of water the mass of KCl will be (1000× 5.7)/94.3 = 60.445 grams.
1 mole of KCl is equal to 74.55 g,
therefore, 60.445 g will be 60.445/74.55 = 0.8108 mole of KCl
Hence, 0.8108 moles of KCl should release twice that number of moles 1.6216 moles ions.
Having 1.6216 moles of KCl ions dissolved in 1000g of water, gives us 1.6216 molar if solution.
Using the freezing point depression constant of water.
dT = Kf (molarity)
dT = (1.86 C/ molar) (1.6216 m)
dT = 3.016 C drop in freezing point
Therefore, it should freeze at - 3.016 Celsius